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forsale [732]
4 years ago
11

A gas occupies a volume of 2.4l at 14.1kPa. What volume will the gas occupy at 84.6kPa?

Chemistry
1 answer:
NikAS [45]4 years ago
6 0
<span>You plug this into the ideal gas law, Pv=nrt, (pressure*volume=moles*gas constant*Temperature) because every thing except volume and pressure remain the same, 2.4*14.1=84.6*V. solve for v, and you get .4 L.</span>
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A mixture of three noble gases has a total pressure of 1.25 atm. The individual pressures exerted by neon and argon are 0.68
FinnZ [79.3K]

First of all, as you seen the gases are noble which means that will not react with each other and in this case each gas create individual pressure.  

P_{T}= total pressure  

P_{Ne} = pressure of neon  

P_{Ar} = pressure of argon  

P_{He} = pressure of helium {which is required}

P_{T} = P_{Ne} + P_{Ar} + P_{He}    

1.25 = 0.68 + 0.35 +  P_{He}

P_{He}   = 1.25  - [0.68 + 0.35] = 0.22 atm

4 0
3 years ago
If a car passes a pedestrian, a change in pitch is __________.
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Given two questions:

<span>1) If a car passes a pedestrian, a change in pitch is ______________. 
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3 years ago
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What is the name for the prevailing global wind pattern that comes from the poles and blows from east to west?
Fittoniya [83]

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3 years ago
What is the part of the cartridge that actually flies outward (the projectile)?
zhannawk [14.2K]

Answer:

the culotte, the fulminant capsule and the sheath or cap together with remains of powder

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3 years ago
Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°C and the melting point take
tresset_1 [31]

Answer:

The molality of isoborneol in camphor is 0.53 mol/kg.

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Melting point of pure camphor= T =179°C

Melting point of sample = T_f = 165°C

Depression in freezing point = \Delta T_f=?

\Delta T_f=T- T_f=179^oC-165^oC=14^oC

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  organic compounds)

\Delta T_f=14^oC

14^oC=1\times 40^oC kg/mol\times m

m=\frac{14^oC}{1\times 40^oC kg/mol}=0.35 mol/kg

The molality of isoborneol in camphor is 0.53 mol/kg.

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3 years ago
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