3 years ago

What are the roots of f(x)=x^2-48 CANT MOVE ON TILL I ANSWER

1 answer:

4 0

Here is your answer, I graphed it

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evablogger [386]

1463 (1064 divided by 8= 133, 133x11)

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3 years ago

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

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2 years ago

Levart [38]

Distribute
10+4x+4+5

Combine like terms
19+4x

Final answer: 4x+19

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3 years ago

Zielflug [23.3K]

Answer:

-1

Step-by-step explanation:

-2 divided by 2 = -1.

A negative divided by a positive equals a lesser negative.

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3 years ago

svetoff [14.1K]

Answer:(x^5−4) and (x^10+4x^5+16)

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3 years ago