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3 years ago

9.6 Code Practice: Question 1

Computers and Technology

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

import java.util.Random;
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
int n = 10;
int [] myArray = new int[n];
buildArray(myArray, n);
System.out.println(Arrays.toString(myArray));
}
public static void buildArray(int[] arr, int n){
for(int i=0; i < arr.length; i++){
Random rand = new Random();
arr[i] = rand.nextInt(90) +10;
}
}
}

Explanation:

Firstly, create a method buildArray that take two inputs, an array and an array size (Line 12). In the method, use random nextInt method to repeatedly generate a two digit random number within a for loop that will loop over array size number of times (Line 13-15). The expression rand.nextInt(90) + 10 will generate digits between 10 - 99.

In the main program, call the build array method by using an array and array size as input arguments (Line 8). At last, print the array after calling the buildArray method (Line 9).

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Using C++

sweet-ann [11.9K]

Answer:

#include<iostream>

using namespace std;

void OutputMinutesAsHours(double origMinutes) { //Same as question

double hours=origMinutes/60; //solution is here

cout<<hours;

}

//Below is same as mentioned in question

int main() {

OutputMinutesAsHours(210.0);

cout << endl;

return 0;

}

OUTPUT :

3.5

Explanation:

In the above code, only two lines are added. To convert minutes into hours we have to divide them 60, so we take minutes as input and define a new variable of double type which stores minutes converted to hours and then that variable is printed to console. For 210, it gives 3.5, similarly for 3600 it gives 60 and so on.

6 0

3 years ago

Which is true for a hosted blog software

professor190 [17]

Since you have not provided the choices wherein I will have to choose from to arrive at an answer, I will just explain to you the concept revolving around a hosted blog software. Hosted blog software are basically installed by the owner of the web server in which among its famous platforms is the Blogger.

7 0

3 years ago

Read 2 more answers

A screen capture is a digital image of your screen, as if you took a picture of it with a camera. For instance, you might want t

GrogVix [38]

The given narration talks about the different means of taking a screen capture on a Windows environment.

<h3>What is a Screen Capture?</h3>

This refers to the process where the content of a screen is captured in a digital image form that is saved in the Documents of the computer as a screenshot.

Hence, we can see that the author mentioned the various ways of using the snipping tool to capture whole or part screens and the precise procedure on how to do it.

Read more about screen capture here:

brainly.com/question/22654940

#SPJ1

5 0

2 years ago

When engineers consider _____, they propose giving up a benefit of one proposed design in order to obtain a benefit of a differe

spin [16.1K]

Answer:

The answer is A. Constraint.

5 0

2 years ago

Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument

timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0

3 years ago