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2 years ago

9

How is social media changing the world as we know it?

1 answer:

Vika [28.1K]2 years ago

4 0

Answer:

Social media has helped many businesses grow and promote itself, and has helped people find a better way to connect and communicate with one another. On the other hand, it's also provided many people with problems involving mental health, emotional insecurities, and waste of time

Explanation:

what they said is correct

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Can someone help me in this one :)

djyliett [7]

I believe it is “runs on parallel circuits”! my bad if incorrect

3 0

2 years ago

You are at the controls of a particle accelerator, sending a beam of 2.10×107 m/s protons (mass m) at a gas target of an unknown

Kipish [7]

Answer:

a

The mass is $m_2 =21.75*10^{-27} \ kg$

b

The velocity is $v_2 = 3.0*10^{6} m/s$

Explanation:

From the question we are told that

The speed of the protons is $u_1 = 2.10*10^{7} m/s$

The mass of the protons is $m$

The speed of the rebounding protons are $v_1 = -1.80 * 10^{7} \ m/s$

The negative sign shows that it is moving in the opposite direction

Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as

$m_2 = [\frac{u_1 -v_1}{u_1 + v_1} ] m_1$

Where $m_1$ is the mass of a single proton

So substituting values

$m_2 = \frac{2.10 *10^{7} - (-1.80 *10^{7})} {(2.10 *10^7) + (-1.80 *10^{7})} m_1$

$m_2 =13 m_1$

The mass of on proton is $m_1 = 1.673 * 10^{-27} \ kg$

So $m_2 =13 ( 1.673 * 10^{-27} )$

$m_2 =21.75*10^{-27} \ kg$

Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as

$m_1 u_1 + m_2u_2 = m_1 v_1 + m_2v_2$

Now $u_2$ because before collision the the nucleus was at rest

So

$m_1 u_1 = m_1 v_1 + m_2v_2$

=> $v_2 = \frac{m_1(u_1 -v_1)}{m_2}$

Recall that $m_2 =13 m_1$

So

$v_2 = \frac{m_1(u_1 -v_1)}{13m_1}$

=> $v_2 = \frac{(u_1 -v_1)}{13}$

substituting values

$v_2 = \frac{( 2.10*10^{7} -(-1.80 *10^{7}))}{13}$

$v_2 = 3.0*10^{6} m/s$

7 0

3 years ago

This planet gets its blue-green color because its atmosphere is full of methane gas and hydrogen.

Effectus [21]

The correct is -

Uranus

5 0

2 years ago

Read 2 more answers

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) (A) 0.39

exis [7]

Explanation:

It is given that,

Relativistic Mass of the stone, m₀ = 0.6

Mass, $m=0.76\ kg$

Relativistic mass is given by :

$m=\dfrac{m_o}{\sqrt{1-\dfrac{v^2}{c^2}}}$ .........(1)

Where

c is the speed of light

On rearranging equation (1) we get :

$v^2=c^2(1-(\dfrac{m_o}{m})^2)$

$v=c\sqrt{ (1-(\dfrac{m_o}{m})^2)}$

$v=c\sqrt{ (1-(\dfrac{0.6}{0.76})^2)}$

v = 0.61378 c

or

v = 0.6138 c

So, the correct option is (c). Hence, this is the required solution.

8 0

2 years ago

The box as shown above is moving at a constant velocity . True or false

STatiana [176]

True because on side is heavier than the other

8 0

2 years ago