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yawa3891 [41]
3 years ago
5

An elevator is moving downward when someone presses the emergency stop button. The elevator comes to rest a short time later. Gi

ve the signs for the velocity and the acceleration of the elevator after the button has been pressed but before the elevator has stopped.Enter the correct sign for the elevator's velocity and the correct sign for the elevator's acceleration, separated by a comma. For example, if you think that the velocity is positive and the acceleration is negative, then you would enter +,- . If you think that both are zero, then you would enter 0,0 .
Physics
1 answer:
OLga [1]3 years ago
5 0

Answer:

<em>Answer:  - , + </em>

Explanation:

<u>Velocity and Acceleration </u>

In general terms, velocity and acceleration in the plane are both vectors with two components. They don't have 'sign' but magnitude and direction. If we know motion is restricted to a simple line, then we can define the positive and negative references.

In vertical motion, the positive reference is commonly pointed upwards, but if we chose the opposite way, the results shouldn't change in magnitude, just their signs. Let's choose like proposed, the positive direction upwards.

Since the elevator was moving downwards, its velocity is negative. When the button is pushed, it continues to move downwards, but slower. Its velocity is still negative.

The acceleration has the same sign as the velocity if it tends to increase the magnitude of the object, and is negative in the opposite case. Let's look at the formula

\displaystyle a=\frac{v_f-v_o}{t}

In this case, v_f=0 because the elevator will eventually stop, and v_o is negative. It means the acceleration is

\displaystyle a=\frac{-v_o}{t}

It results in a positive value

\boxed{Answer: -,+}

Note: If we chose the opposite references, then the answer would be: +,-

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4 years ago
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A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh
Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 rad/sec^2

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius r=\frac{d}{2}=\frac{1.63}{2}=0.815m

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec

(b) We know that linear speed is given by

v=r\omega =0.815\times 8.362=6.815m/sec

(c) We have given final angular velocity \omega _f=675rev/min

And \omega _i=79.9rev/min

Time t = 63 sec

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2

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7 0
3 years ago
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Answer:

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Explanation:

Distance between convex and concave mirror is =60cm

Radius of the concave mirror (R) = 200cm

For the concave mirror, u = ∞

V = {R}/{2}=100cm

The object for the convex mirror and the final image is on the pole of the concave mirror, and distance between convex and concave mirror is 60cm

u_1=60-100 =-40cm

Object will be behind the convex mirror

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f=24cms

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6 0
3 years ago
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Answer:

(a) 21.36 ohms

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Explanation:

Parameters given:

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(b) Power is also given as:

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Answer:

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