3 years ago

Is (1, 1) a solution to 3y=2x+1

Mathematics

2 answers:

REY [17]3 years ago

6 0

To check whether (1, 1) is a solution for 3y = 2x +1, You must take the value of x as 1 and the value of y also as 1.

Substituting these values of x and y, we get,

3*1 = 2*1 + 1

3 = 2 + 1 which is true.

Therefore, (1, 1) is a solution of 3y = 2x + 1

Snowcat [4.5K]3 years ago

3 0

Yes.
3y=2x +1
3 (1) = 2 (1) +1
(3,3)
(1,1) is a solution

You might be interested in

john collecrs cards. he collects 44 red, 67 blue cards, and 52 yellow. he puts 9 in protective sheets how many full sheets does

Kobotan [32]

Answer:

He has 18 full sheets.

Step-by-step explanation:

44 + 52 + 67 = 163

163/9 = 18.11

The question specifically asks for a whole number, not a decimal or fraction, so the answer is 18 full sheets.

8 0

3 years ago

You a Miguel Cervantes de Navas y Colon, captain in the Royal Spanish Army in Seville in the year 1842. Outside your barracks wi

djverab [1.8K]

650 cannonballs

Explanation step by step:

upper layer = 1 ^ 2

second layer = 2 ^ 2

third layer = 3 ^ 2

layer 12 is 12 ^ 2

The formula is:

n * (n + 1) * (2n + 1) / 6 

n = 12 

12 (12 + 1) (2 * 12 + 1) / 6 

12 * 13 * 25/6 = 

650 

 

There are 650 cannonballs in this pyramid.

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to (256x^16)^1/4 A.4x^2 B.4x^4 C. 64x^2 D. 64x^4

antiseptic1488 [7]

Given expression: $(256x^{16})^{1/4}$ .

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=256^{\frac{1}{4}}\left(x^{16}\right)^{\frac{1}{4}}$

$256=4^4$

$256^{\frac{1}{4}}=\left(4^4\right)^{\frac{1}{4}}=4$

$\left(x^{16}\right)^{\frac{1}{4}}=x^{16\cdot \frac{1}{4}}=x^4$

$(256x^{16})^{1/4} =4x^4$

<h3>Therefore, correct option is B option : B.4x^4</h3>

6 0

3 years ago

Read 2 more answers

AssAssessment captures blank growth

jekas [21]

What do you mean by this

6 0

3 years ago

What’s the answer to this math problem

LuckyWell [14K]

Y/x^2

You have to subtract or add exponents

8 0

3 years ago

Read 2 more answers