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WINSTONCH [101]
3 years ago
7

Paula a college student earned $3,600 she spent 2,500 for tuitution 600 for rent and 430 for food the rest went for miscellaneou

s expenses ehat are the fractions?
Mathematics
1 answer:
posledela3 years ago
8 0

25/36 6/36 and 4.3/36 are the fractions i think.

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what is the units digit of the sum of 1!+2!+3! ... n! when n=2019. Include an explanation and what a unit digit is.
horsena [70]

Hey!

Finding the factorial for the first few numbers, we have:

1!=1

2!=2

3!=6

4!=24

5!=120

6!=720

7!=720*7

8!=720*56

What we can see as a clear pattern from 5! and on is that our number ends with a 0, making the units digit 0. Therefore, when we add the units digit of 5! and on, we have a result of 0. So, we can simply add the units digits of 1!, 2!, 3!, and 4!, which is 1+2+6+4=13. Since the units digit is the last number, we can drop the tens place to get an answer of 3.


Feel free to ask further questions!

8 0
4 years ago
How many different 2-person conversations would happen at a party of 30 people
tigry1 [53]
15 because simple division 30 divided by 2 is 15 only 15 can happen
7 0
3 years ago
Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf
erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

(\overline{x}_1-\overline{x}_2)\pm t^*\times SE ,

where (\overline{x}_1-\overline{x}_2) = sample mean difference .

t^*= critical t value (two-tailed)

SE= Standard error.

Given : (\overline{x}_1-\overline{x}_2)=23

t^*=2.262

SE= 4.2

Now, the confidence interval for mean difference will be :-

23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)

Hence, the required confidence interval : (13.4996, 32.5004)

8 0
3 years ago
Trucks are delivering gravel to a construction site each truck hold 7.5 cubic yards of gravel. The weight of 1 cubic yard of gra
Romashka-Z-Leto [24]
The first thing you must do is to calculate the weight of the gravel (w) that the truck holds (7.5 yards³). So, you have:

 If the weight of 1 yard³ is 1.48 tons, then the weight of 7.5 yards³ is:

 w=7.5x1.48 tons
 w=11.1 tons

 The problem says that the gravel will be placed in containers that each hold 3.7 tons of gravel,so, If they need 1 cotainer to place 3.7 tons, how many containers they need to place 11.1 tons?

 1 container-------3.7 tons of gravel
                 x-------11.1 tons of gravel

 x=(11.1x1)/3.7
 x=11.1/3.7
 x=3 containers

 H<span>ow many containers of this size are needed to hold all the gravel from one truck?
</span>
 The answer is: 3 containers. 
7 0
4 years ago
Let f(x) = 3x - 10. Find the value of f(-3).
laiz [17]
Easy, sub -3 for x
f(-3)=3(-3)-10
f(-3)=-9-10
f(-3)=-19

the value of f(-3) is -19
6 0
3 years ago
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