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vfiekz [6]
4 years ago
10

Lightning is an example of matter in a liquid state.

Physics
2 answers:
True [87]4 years ago
8 0

Answer:

False

Explanation: Lightening is not an example of matter in solid or liquid state. It is a phenomenon of spark of electricity in the atmosphere. Lightening can also be seen in volcanic eruptions,forest fires, thunderstorms, hurricanes etc. In the initial stage of development of lightening air acts as an insulator between positive and negative charge but when charge develops enough it break the wall of insulator air and sparking occurs.

tester [92]4 years ago
7 0
False, lightning is not an <span>example of matter in a liquid state. Rather, it is an example of matter in a state of plasma. </span>It<span> is a form of matter in which many of the electron s wander around freely among the nuclei of the atoms. Hope this answers the question.</span>
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78. A film of oil on water will appear dark when it is very thin, because the path length difference becomes small compared with
Hoochie [10]

To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.

Mathematically this expression can be described under the equation

\delta = 2nt

Where

n = Refractive index

t = Thickness

In terms of the wavelength the path difference of the reflected waves can be described as

\delta = \frac{\lambda}{4}

Where

\lambda = Wavelenght

Equation the two equations we have that

2nt = \frac{\lambda}{4}

t = \frac{\lambda}{8n}

Our values are given as

\lambda = 380nm \rightarrow Wavelength of light

n = 1.4

t = \frac{380nm}{8*1.4}

t = 33.93nm

Therefore the minimum thickness of the oil for destructive interference to occur is approximately 34.0 nm

4 0
3 years ago
Which describes the molecular motion of a solid nickel marble rolled across the floor?
Gemiola [76]
I can't decide between A and B, but B seems more likely to me. Even though the molecules don't look like they're moving, the area of contact is slightly more compressed.
7 0
4 years ago
A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?
Alisiya [41]

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

7 0
3 years ago
Crushing, stirring, heating are all methods to increase the rate of ______________ a solute in a solvent.
Fofino [41]

Answer: mixing

Explanation:

4 0
3 years ago
A lead ball is dropped into a lake from a diving board 5.0 meters above the water. After entering the water, it sinks to the bot
xxMikexx [17]

Answer:

28.8 meters

Explanation:

We must first determine at which velocity the ball hits the water. To do so we will:

1) Assume no air resistance.

2) Use the Law of conservation of mechanical energy: E=K+P

Where

E is the mechanical energy (which is constant)

K is the kinetic energy.

P is the potential energy.

With this we have \frac{m}{2} *v^{2}  = m*g*h

Where:

m is the balls's mass <- we will see that it cancels out and as such we don't need to know it.

v is the speed when it hits the water.

g is the gravitational constant (we will assume g=9.8\frac{m}{s^{2} }.

h is the height from which the ball fell.

Because when we initially drop the ball, all its energy is potential (and P = - m*g*h) and when it hits the water, all its energy is kinetic (K=\frac{m}{2} *v^{2}. And all that potential was converted to kinetic energy.

Now, from \frac{m}{2} *v^{2}  = m*g*h we can deduce that v=\sqrt{2*g*h}

Therefore v=9.6\frac{m}{s}

Now, to answer how deep is the lake we just need to multiply that speed by the time it took the ball to reach the bottom.

So D=9.6\frac{m}{s}*3s=28.8m

Which is our answer.

7 0
3 years ago
Read 2 more answers
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