We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
Answer:
<em>The correct option is C) spreads out over a large area on the object. </em>
Explanation:
In physics, a ground can be described as a reservoir object in which charge can be stored. Grounding refers to the removal of charge in an object by using the ground object. When an object with excess if charge is placed on the ground object, the electrons are transferred from the charges object to the ground object. This charge begins to spread evenly in the ground object with the passage of time.
Answer:
option A
Explanation:
given,
angular speed is constant
initial distance = r
final distance (r')= 2 r
initial linear velocity = v
final linear velocity = v'
we know,
v = r ω......................(1)
where r is the distance
ω is the angular speed
now,
v' = r' ω
v' = 2 r ω
v' = 2 v
hence, the linear velocity doubles.
The correct answer is option A
