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geniusboy [140]
3 years ago
15

Americans eat too much salt (NaCl). A healthy adult should eat no more than 6 g of salt in one day. Use this information to answ

er the following questions. (Round atomic masses to the nearest tenth unit.)
a. What is the molar mass of NaCl?
b. What is the maximum number of moles of NaCl an adult should consume in one day?
Chemistry
1 answer:
Rufina [12.5K]3 years ago
7 0

Answer:

a. 58.5 g/mol

b. 0.1 mol

Explanation:

a.

The molar mass of Na is 23.0 g/mol. The molar mass of Cl is 35.5 g/mol. The molar mass of NaCl is:

M(Na) + M(Cl) = 23.0 g/mol + 35.5 g/mol = 58.5 g/mol

b. A healthy adult should eat no more than 6 g of salt in one day. The moles corresponding to 6 g of NaCl are:

6 g × (1 mol/58.5 g) = 0.1 mol

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Along with subduction, what other process changes sedimentary rocks to metamorphic rocks?
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It would be weathering because of all the heat and pressure.
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Which of the following could be considered a scientific statement? (2 points) ​
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The answer of the scientific STATEMENT is" Appears That Ants Live In Colonies."

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A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8
Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8  mg/L

Volume of solution treated everyday , V= 80 million gal

= 80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L

1 gallon = 4.546 Liter

Mass of  calcium ion in V = 46.9 mg/L\times 3.637\times 10^8 L

=  1.706\times 10^{10} mg

1 mg = 0.001 g

1.706\times 10^{7} g

Moles of calcium ions = \frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

\frac{1}{1}\times 426,500 mol=426,500 mol of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol  = 42,650,000 g = 42,650 kg

Mass of  magnesium ion in V = 14.8 mg/L\times 3.637\times 10^8 L

= 5.382\times 10^{9} mg

=  5.382\times 10^{6} g

Moles of magnesium ions = \frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

\frac{1}{1}\times 224,250 mol=224,250 mol of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol  = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

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3 years ago
The boiling point of another member of this homologous series was found to be 309 KK. What is the likely molecular formula for t
Ganezh [65]

Answer: Pentane C5H12

Explanation:

The boiling point of a substance is simply defined as the temperature whereby a liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid will changes into vapor.

The likely molecular formula for this compound is Pentane i.e C5H12 due to the fact that its boiling point is between Butane with formula C4H10 and Hexane with formula C6H14 boiling points.

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3 years ago
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