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Fantom [35]
3 years ago
14

Helppppp asappp idkkkll how to do thisssss!!!

Chemistry
1 answer:
horsena [70]3 years ago
5 0
It is b i am pretty sure
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1. Determine the amount concentration of calcium ions and acetate ions in a 0.80 mol/L
PIT_PIT [208]

Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

<h3>What is concentration?</h3>

The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.

Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.

Thus;

Ca(CH3COO)2(aq)  ----> Ca^2+(aq) + 2CH3COO^-(aq)

It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

Learn more about concentration:brainly.com/question/10725862

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6 0
2 years ago
Would the water in a pond or the water in a full bathtub have more thermal energy? Explain why.
Mekhanik [1.2K]
Thermal energy is defined as the total kinetic energy of all particles in an object. Even though the cup of water has a higher temperature, the bathtub has more thermal energy because it contains much more mass of water compared to the cup.
5 0
2 years ago
4. Calculate the final concentration if water is added to 1.5 L of a 12 M
konstantin123 [22]

Answer:

6M

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

Molarity dilute soln = [(M x V)conc/V (dilute)] = 1.5L x 12M / 3.0L = 6M final dilute soln

6 0
4 years ago
Select The on that most applys<br><br><br> Will mark brainliest
zepelin [54]

Answer:

A and B

Explanation:

3 0
3 years ago
To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?
poizon [28]
We know that to relate solutions of with the factors of molarity and volume, we can use the equation: M_{1}  V_{1} = M_{2}  V_{2}

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M H_{2}  SO_{4} is the left side of the equation. Then we have:

(18 M)(0.050 L)=(4.35M) V_{2}

We can then solve for V_{2}:

V_{2}= \frac{(18M)(0.05L)}{4.35M} and V_{2} =0.21 L or 210 mL

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.


7 0
4 years ago
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