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3 years ago

Helppppp asappp idkkkll how to do thisssss!!!

Chemistry

1 answer:

horsena [70]3 years ago

5 0

It is b i am pretty sure

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Radiation is a measure of average kinetic energy of particles in an object true or false

laila [671]

Answer:false

Explanation:

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3 years ago

A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253

german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L$

So, the new volume is 1.45 L.

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3 years ago

At what temperature in the Kelvin scale does water boil? Explain what happen when we supply heat energy to water till it changes

erma4kov [3.2K]

100 +273=373 kelvins

7 0

3 years ago

Using the periodic table, determine which material is most likely to be a good conductor. A. sodium B. bromine C. carbon D. oxyg

grandymaker [24]

A. Because sodium is a metal and metals are good conductors

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3 years ago

The thallium (present as Tl2SO4) in a 9.486-g pesticide sample was precipitated as thallium(I) iodide. Calculate the mass percen

tino4ka555 [31]

Answer: The mass percentage of $Tl_2SO_4$ is 5.86%

Explanation:

To calculate the mass percentage of $Tl_2SO_4$ in the sample it is necessary to know the mass of the solute ( $Tl_2SO_4$ in this case), and the mass of the solution (pesticide sample, whose mass is explicit in the letter of the problem).

To calculate the mass of the solute, we must take the mass of the $TlI$ precipitate. We can establish a relation between the mass of $TlI$ and $Tl_2SO_4$ using the stoichiometry of the compounds:

$moles\ of\ TlI = \frac{0.1824 g}{331.27\frac{g}{mol} } = 5.51*10^{-4}\ mol.$

Since for every mole of Tl in $TlI$ there are two moles of Tl in $Tl_2SO_4$ , we have:

$moles\ of\ Tl_2SO_4 = 2 * moles\ of\ TlI = 1,102*10^{-3}\ mol$

Using the molar mass of $Tl_2SO_4$ we have:

$mass\ of\ Tl_2SO_4 = 1,102*10^{-3}\ mol * 504.83\ \frac{g}{mol}= 0.56\ g$

Finally, we can use the mass percentage formula:

$mass\ percentage = (\frac{solute\ mass}{solution\ mass} )*100 = (\frac{mass\ of\ Tl_2SO_4}{pesticide\ sample\ mass})*100 = (\frac{0.56g}{9.486g})*100 = 5.86\%$

6 0

3 years ago