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Ostrovityanka [42]
4 years ago
11

Which statement best explains why different gases effuse at different rates?

Chemistry
2 answers:
arlik [135]4 years ago
6 0
Your answer is A. <span>At a given pressure, gas particles with smaller masses move faster.

Hope this helps.

</span>
matrenka [14]4 years ago
6 0

Answer: Different gases effuse at different rates because at a given temperature, gas particles with smaller masses move faster.

Explanation: The motion of particles in a gas depends on the kinetic energy of the gas particles which further depend on the temperature of the gas. Thus, the rate of gas given by Graham's law can only be stated when the two gases are at fixed temperature.

Graham's Law: This law states that the rate of effusion of gas is inversely proportional to the square root of its mass.

Mathematically,

\frac{(Rate)_1}{(Rate)_2}=\sqrt{\frac{M_2}{M_1}}

From the above relation, the gas particle with smaller mass will effuse faster at a given temperature.


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The following reaction mixture contains 0.22 M CH4, 0.67 M CO2 and 1.3 M H2O. Which of the following statements is TRUE concerni
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Reaction is shifting left toward reactant side

Explanation:

4CuO(s) + CH₄(g) <=?=> CO₂(g) + Cu(s) + 2H₂O(g)

---------      0.22M             0.67M     -------    1.30M

Qc = [O₂(g)][H₂O(l)]²/[CH₄(g)] = (0.67)(1.30)²/(0.22) =5.12

Kc = 1.1 < Qc = 5.12 => Reaction is shifting LEFT and reactant concentrations are increasing with product concentrations decreasing. Qc will be decreasing and final Kc value will be lower than original Qc upon reaching equilibrium stability.  

_____________________

FYI Note => For reaction mixtures the following is a good guide to reaction response to applied system stress. Note the conclusion follows the direction the inequality symbol is pointing.  

Kc  <  Qc  => Rxn system is shifting Left

Kc =   Qc  => Rxn system is at equilibrium

Kc >  Qc  => Rxn system is shifting Right

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it's true ....

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