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notka56 [123]
2 years ago
6

Name the follwing compound, KBr​

Chemistry
1 answer:
ddd [48]2 years ago
7 0

Answer:

Potassium bromide

Explanation:

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two people start out 100 meters apart from each other and start moving towards each other at the same time. One person is moving
andreev551 [17]

Answer:

1.332 meters per second. // 2.664 meters per second.

Explanation:

the slower person moved 33.3 meters, and the faster person moved 66.6 meters.

the slower person is moving 33.3 meters in 25 seconds, while the other person is moving 66.6 meters in 25 seconds

slower person moved 33.3/25 = 1.332 meters per second.

faster person moved 66.6/25 = 2.664 meters per second.

4 0
3 years ago
How are the orbits of asteroids similar to, or different from planetary orbits?
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Aside from banks, what are 2 other places you might be able to borrow
money? And can you help with more questions on my page thank you so much I really appreciate you and everything you do for this app
7 0
3 years ago
What is the area of triangle ABC with vertices A(x¹,y¹), B(x²,y²)and C (x³,y³)??????????<br>​
AlexFokin [52]

Answer:

Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|

Area = 2\ units^2

Explanation:

Given

A = (x_1,y_1)

B = (x_2,y_2)

C = (x_3,y_3)

Required

Determine the area

The area of a triangle is :

Area = \frac{1}{2}|A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|

By substituting values for the x and y coordinates of A, B and C;

We have:

Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|

So:

For instance

A = (0,3)

B= (2,1)

C = (2,3)

The area is:

Area = \frac{1}{2}|0(1-3) + 2(3-3) + 2(3-1)|

Area = \frac{1}{2}| 2*0 + 2*2|

Area = \frac{1}{2}| 0 + 4|

Area = \frac{1}{2}|4|

Area = \frac{1}{2} * 4

Area = 2\ units^2

7 0
3 years ago
How many moles of N2O5 are needed<br> to produce 7.90 g of NO2?
Roman55 [17]

Answer:

0.085 moles of  N₂O₅ are needed

Explanation:

Given data:

Mass of NO₂ produces = 7.90 g

Moles of N₂O₅ needed = ?

Solution:

2N₂O₅       →     4NO₂  + O₂

Number of moles of NO₂ produced :

Number of moles = mass/ molar mass

Number of moles = 7.90 g/ 46 g/mol

Number of moles = 0.17 mol

now we will compare the moles of NO₂   with N₂O₅.

                NO₂          :       N₂O₅

                  4            :          2

                0.17          :         2/4×0.17 = 0.085 mol

Thus, 0.085 moles of  N₂O₅ are needed.

4 0
3 years ago
If a buffer solution is 0.130 M in a weak acid (K_a = 1.7 x 10^-5) and 0.590 M in its conjugate base, what is the pH?
Serggg [28]
Use the Henderson-Hasselbach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.7 x 10^-5) + log(0.590/0.130) = 5.43
8 0
3 years ago
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