By increasing temperature, molecules of the solution no longer forms aggregates and solution becomes unsaturated.
Answer:
B) Earth and all the other planets orbit the Sun.
Explanation:
A) This one is basically what people used to think, that the sun and other planets orbited around Earth. We know now that this is not true.
C) We know that no planets orbit around Earth.
D) The Sun does not orbit around Earth, the Earth orbits around the Sun.
The acid/base pair that give equivalence point that Cannot be predicted by general knowledge is NaOH and HCI ONH.
<h3>What is an Acid and base?</h3>
An Acid is a substances that is corrosive in nature and turn blue lithmus paper to red which it react with base to produce salt and water.
Acid dissolve metals.
Base is a substance that turn red lihthmus paper to blue and react with acid to produce salt and water.
Therefore, The acid/base pair that give equivalence point that Cannot be predicted by general knowledge is NaOH and HCI ONH.
The question is incomplete as the options were not given. The options were gotten from another website.
Select the correct answer below:
ONaOH and HCI ONH,
HC ONH, and CH, COOH
NaOH and Christmas, COOH
Learn more about acid and base below.
brainly.com/question/2506771
Answer:
The mass of ascorbic acid in 2.87×10−4 mol are 50,5 mg
Explanation:
Molar mass = 176 g/mol
Moles . molar mass = grams.
2,87 x10*-4 m . 176 g/m = 50,5 x10*-3 grams
A human can take one sweet lime and half to cover the daily requirement of vitamin C. =)
Answer:
Explanation:
To calculate pH you need to use Henderson-Hasselbalch formula:
pH = pka + log₁₀ ![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
Where HA is the acid concentration and A⁻ is the conjugate base concentration.
The equilibrium of acetic acid is:
CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75
Where <em>CH₃COOH </em>is the acid and <em>CH₃COO⁻ </em>is the conjugate base.
Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:
pH = 4,75 + log₁₀ ![\frac{[CH_{3}COO^-]}{[CH_{3}COOH]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH_%7B3%7DCOO%5E-%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D)
a) The pH is:
pH = 4,75 + log₁₀ ![\frac{[2 mol]}{[2 mol]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20mol%5D%7D%7B%5B2%20mol%5D%7D)
<em>pH = 4,75</em>
<em></em>
b) The pH is:
pH = 4,75 + log₁₀ ![\frac{[2 mol]}{[1mol]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20mol%5D%7D%7B%5B1mol%5D%7D)
<em>pH = 5,05</em>
<em></em>
I hope it helps!
