Question

The production of ammonia (NH3) under standard conditions at 25°C is represented by the following thermochemical equation. N2(g) + 3 H2(g) → 2 NH3(g); ΔH = −91.8 kJ How much heat is released when 1.663 ✕ 104 grams of ammonia is produced?

Answer 1

Answer:

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.

Explanation:

Moles of ammonia  gas produced :

$\frac{1.663\times 10^4 g}{17 g/mol}=978.235 mol$

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.

So, When 978.235 moles of ammonia gas is produced the energy released will be:

$\frac{-91.8 kJ}{2}\times 978.235 mol=-44,900.98 kJ\approx -44,901 kJ$

(negative sign indicates that energy is released as heat)

44,901 kilo Joule heat is released when $1.663\times 10^4 g$ grams of ammonia is produced.