Answer:
The angle is degrees.
Explanation:
Se the attached drawing if you need a visual aid for the explanation. Let be the angle of elevation of the plante which in itself is the same drop angle that the pilot measures. Let be the horizontal distance from the target and the height of the plane. We know that the package is dropped without any initial vertical speed, that means that it has a y-position equation of the form:
If we set we are setting the condition that the package is in the ground. We can then solve for t and get the flight time of the package.
.
If the flight time is - then the distance b can be found in meters by taking into account that the horizontal speed of the plane is .
The angle is thus
degrees.
Answer:
4.9 m/s
Explanation:
Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the ball in this problem,
u = 0 (it starts from rest)
is the acceleration
s = 3 m is the distance covered
Solving for v,
Rolling friction is less than sliding friction
Answer:
Explanation:
Atmospheric pressure = 7 x 10⁴ Pa
force on a disk-shaped region 2.00 m in radius at the surface of the ocean due to atmosphere = pressure x area
= 7 x 10⁴ x 3.14 x 2 x 2
= 87.92 x 10⁴ N
b )
weight, on this exoplanet, of a 10.0 m deep cylindrical column of methane with radius 2.00 m
Pressure x area
height x density x acceleration of gravity x π r²
= 10 x 415 x 6.2 x 3.14 x 2 x 2
=323168.8 N
c ) Pressure at a depth of 10 m
atmospheric pressure + pressure due to liquid column
= 7 x 10⁴ + 10 x 415 x 6.2 ( hρg)
= 7 x 10⁴ + 10 x 415 x 6.2
(7 + 2.57 )x 10⁴ Pa
9.57 x 10⁴ Pa
A and C
Each equinox doesn’t point towards or away from the sun