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Anna35 [415]
3 years ago
7

After a hold up, Robin Banks flees in his 1575 kg getaway car at 20 m/s. He crashes into a 45 kg highway barrel which is at rest

. If Robin Bank’s car moves at 18.9 m/s after the collision, how fast does the barrel move after being hit?
Physics
2 answers:
fiasKO [112]3 years ago
7 0

Answer:

v = 38.9 m/s

Explanation:

Dimas [21]3 years ago
6 0

v = 38.5 m/s

Explanation:

P1 = P2 (conservation law of linear momentum)

(1575 kg)(20 m/s) + (45 m/s)(0) = (1575 kg)(18.9 m/s) + 45v

Solving for v

v = 38.5 m/s

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What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic
VladimirAG [237]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   v_w  =  2.256 *10^{8} \  m/s

B

  v_e  =  2.21 *10^{8} \  m/s

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  n_w  =  1.33

      The  refractive  index of ethanol is  n_e  =  1.36

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       v_w  =  \frac{c}{n_w }

Where  c is the speed of light with value  c =  3.0 *10^{8} \  m/s

       v_w  =  \frac{3.0 *10^{8}}{1.33 }

       v_w  =  2.256 *10^{8} \  m/s

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            v_e  =  \frac{ c}{n_e }

  =>       v_e  =  \frac{3.0 *10^{8}}{1.36 }

=>          v_e  =  2.21 *10^{8} \  m/s

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Kisachek [45]

Yeah

All they are all correct

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Answer:

D

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