Ask question

Ask question

All categories

3 years ago

7

If the core of a supernova contains about one solar mass, the core will become a

2 answers:

irina [24]3 years ago

3 0

A solar mass of above 1.4 will become a neutron star according to the Chandrasekhar limit, therefore if there is 1 solar mass it will collapse to form a white dwarf.a solar mass of above 1.4 will become a neutron star according to the Chandrasekhar limit, therefore if there is 1 solar mass it will collapse to form a white dwarf.

Hope this helps!

grin007 [14]3 years ago

3 0

Answer:

It will become a neutron star

Explanation:

For the solar mass of anything above 1.4, the mass will automatically become a neutron star. This is according to the Chandrasekhar limit. This limit determines that 1 solar mass will collapse to form a white dwarf of a solar mass above 1.4 .

You might be interested in

A 5.93 kg ball is attached to the top of a vertical pole with a 2.35 m length of massless string. The ball is struck, causing it

Delvig [45]

Answer

given,

mass of ball = 5.93 kg

length of the string = 2.35 m

revolve with velocity of 4.75 m/s

acceleration due to gravity = 9.81 m/s²

T cos θ = mg

T cos θ = $5.93\times 9.81$

T cos θ = 58.17

$T sin \theta =\dfrac{mv^2}{r}$

$T sin \theta =\dfrac{5.93\times 4.75^2}{2.35 sin \theta}$

$T sin^2 \theta =56.93$

$sin^2 \theta = 1 - cos^2 \theta$

$T (1 - cos^2 \theta) =56.93$

$T (1 - (\dfrac{58.17}{T})^2) =56.93$

T² - 56.93T - 3383.75 = 0

T = 93.22 N

$cos \theta = \dfrac{58.17}{93.22}$

θ = 51.39°

6 0

3 years ago

A person's speed around the Earth is faster at the poles than it is at the equator.

VashaNatasha [74]

Answer:

no

Explanation:

it is faster at the equator

6 0

2 years ago

A body weights 50 N in air and 45 N when wholly immersed in water calculate (i) the loss in weight of the body in water (ii) the

Lelechka [254]

Answer:

$difference \: in \: weight = 150n - 100n = 50n$

Now,buyantant force

$difference \: in \: weight \: = volume(body) \times density \: of \: water \: \times g$

so;

$50 = {v}^{b} \times 1 \times {10}^{3} \times 9.8m {s}^{2}$

${v}^{b} = \frac{50}{1000 } \times 9.8$

$= \frac{50}{9800}$

$= 0.0051$

Now,

$mass \: in \: air \: = 150n = \frac{150}{9.8kg}$

$density = \frac{weght}{volume}$

$= \frac{150}{0.0051} \times 9.8 \\ x = 3000$

And now,

$specific \: density \: = \frac{density of \: the \: body}{density \: of \: water}$

$= \frac{3000}{1000}$

$= 3$

Hence that,specific density of a given body is 3

please mark me as brainliest, please

3 0

2 years ago

A falling raisin will have<br> whale. (more/less)<br> momentum than a falling blue

Natalka [10]

Answer:less

Explanation:thats the answer

3 0

2 years ago

3. A fighter jet covers a distance of 895m while accelerating from 22m/s to 35m/s. How long (in

larisa86 [58]

Answer:

31.404 seconds

Explanation:

To answer this equation, SUVAT is your best option utilizing and rearranging the known values to solve for the unknown.

here we have the values for

s=895

u=22

v=35

t= the unknown value

in this instant the equation s=0.5 x (u+v)t is the best equation to use

so we sub in the known values

895=0.5 x (22+35)t

rearrange to solve for t

895=28.5t

895/28.5=t

t=31.404 seconds (rounded to 3 decimal places)

6 0

2 years ago