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Nimfa-mama [501]
3 years ago
9

Fill in the blanks! Please, help me ASAP ✌

Physics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

I don't know

Explanation:

i don't know this question answer for here

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You have two beakers of different types of oil, which have different specific heat capacities. You put each beaker in a water ba
eimsori [14]

Answer:

C

Explanation:

C:If the mass of oil in the two beakers is the same, the oil with the lower specific heat capacity will heat up more quickly.

The answer is C

8 0
3 years ago
I need help!<br> Pleeeeeeeeaaaaaaaaaaaaasssssssssssseeeeeeeeeeee?
serious [3.7K]

Answer:

np 500000 eeeeeeeeeeee

Explanation:

346 763 999 eeeeeeeeeeeee

4 0
3 years ago
The Nardo ring is a circular test track for cars. It has a circumference of 12.5 km. Cars travel around the track at a constant
Vera_Pavlovna [14]

Answer:

(a) 12.5 km

(b) 0 km

(c) 27.78 m/s

Explanation:

100 km/h = 100 km/h * 1000m/km * 1/60 h/minute * 1/60 minute/second = 27.78 m/s

7.5 minutes = 7.5*60 = 450 s

(a) Distance is speed times time duration

s = vt = 27.78 * 450 = 12500 m or 12.5 km

(b) As the car is moving in a circular track with circumference of 12.5 km. This means that after the car drives a distance of 12.5km, it's back to the initial point. So the total magnitude of the car displacement is 0 km

(c) 27.78 m/s

8 0
4 years ago
Read 2 more answers
Two charges Q1 = 32 nC and Q2 = 50 nC are in rest on the horizontal axis. The distance between the charges is 0.66 m. What is th
Brilliant_brown [7]

Answer:

E=1485.9N/C

Explanation: =

Electric field E=kQ/r²,

where k is a constant with a value of 8.99 x 10^9 N m²/C²

Q is the point charge

r is the distance between two point charges =0.44m

O=32*10^-9

Hence

E=(32*10^-9*8.99 x 10^9)/0.44²

E=32*8.99/0.1936

E=287.68/0.1936

E=1485.9N/C

Coulomb's law states that: The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.

3 0
4 years ago
Dos cargas puntuales q1 = −50μC y q2 = +30μC se encuentran
alina1380 [7]

Answer:

Datos:

q1 = -50 μC = 50*10^{-6}

q2 = +30 μC = 30*10^{-6}

F = 10 N

a) x si la <em>F = 10N</em>

Aplicando la Ley de Coulomb:

x = \sqrt\frac{k0 * q1 *q2}{F} = \sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{10} = 1,162m

b) x si la <em>F = 20 N</em>

x=<em> </em>\sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{20}<em> </em>= 0,822m

c)x si la <em>F = 50 N</em>

x = \sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{50} = 0,520m

3 0
3 years ago
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