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Nimfa-mama [501]
3 years ago
9

Fill in the blanks! Please, help me ASAP ✌

Physics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

I don't know

Explanation:

i don't know this question answer for here

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How are observation and inference different
DochEvi [55]

When you see a tall, young, skinny man walking along the beach, you
observe that a tall, young, skinny man walked along the beach, and from
your observation, you know that a tall, young, skinny man walked along
the beach.

When you see a beach with nobody there, but there is a line of 5-toed
footprints in the sand along the beach, you infer that a human being
walked along the beach.  If you are a skilled anthropologist, with some
talent and experience in a few other fields whose names escape me at
the moment, you might be able to make some careful measurements of
the length, width, depth, and shape of the footprints, and then you might
be able to infer that the person who walked along the beach was a tall,
young, skinny man.  You would build all of your information from inference,
without any observations at all except for the line of footprints and your
measurements of them.

3 0
4 years ago
A string vibrates at a frequency of 20Hz. what is its period?
Andreas93 [3]
We know, Period = 1/frequency = 1/20 sec.

So, your final answer is 0.05 sec

Hope this helps!
7 0
3 years ago
A small ball is hung by a string from the ceiling of a train car, so that the ball hangs vertically. Moving from rest, the train
kondor19780726 [428]

Answer:

m

Explanation:

5 0
4 years ago
in a historical movie, two knights on horseback start from rest at 88.0 m spartans ride directly toward each other to do battle.
Tema [17]
The distance formula:d = v i · t + a · t² / 2Sir G.: ( v i = 0 )
d G = 0 + 0.3 · t² / 2Sir A. : d A = 0 + 0.2 t² / 288 m = 0.3 t² / 2   + 0.2 t² / 2    / · 2 ( multiple both sides by 2 )176 = 0.3 t² + 0.2 t²176 = 0.5 t²t² = 176 : 0.5t² = 352t = √352t = 18.76 sd G. = 0.3 · 18.76² / 2 = 0.3 · 352 / 2 = 52.8 mAnswer: The knights collide at 52.8 m relative to Sir George`s starting point.


7 0
3 years ago
A 120-kg hollow spherical ball 1 m in diameter accelerates at a constant rate from rest to 5 rpm in 20 s and then continues to r
FromTheMoon [43]

Answer:

Explanation:

a )

moment of inertia of hollow ball

= 2 / 3  mR²  , m is mass and R is radius of the ball

= 2 / 3 x 120 x .5²

= 20 kg m²

b )

5 rpm =      5 / 60 rps

n = .0833

angular velocity ω = 2πn= 2 x 3.14 x .0833=  .523 rad /s

angular acceleration = increase in angular velocity / time

= .523 - 0 / 20

α = .02615 rad /s²

c )

Torque = moment of inertia x angular acceleration

= 20 x .02615

= .523 Nm

d )

θ = 1/2 α t²

= .5 x  .02615 x 20²

= 5.23

2π n = 5.23 where n is required number

n = .83

3 0
3 years ago
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