Answer:
Enthalpy of vaporization = 30.8 kj/mol
Explanation:
Given data:
Mass of benzene = 95.0 g
Heat evolved = 37.5 KJ
Enthalpy of vaporization = ?
Solution:
Molar mass of benzene = 78 g/mol
Number of moles = mass/ molar mass
Number of moles = 95 g/ 78 g/mol
Number of moles = 1.218 mol
Enthalpy of vaporization = 37.5 KJ/1.218 mol
Enthalpy of vaporization = 30.8 kj/mol
It holds its own shape and it’s solid
Answer:
The answer should be D
Explanation:
because turning 1 mole of propane to grams means its still one mole of propane just in a different unit.
Cause latin name of Pb is plumbum.
The same K - potassium - latin name is kalium.
