Answer:
P =
Explanation:
For this exercise we use that the pressure at a given level is the same, so we set a level on both sides of the pressure gauge, just the point where the liquid is on the system side, with a pressure (P)
P =
where is the atmospheric pressure in pascals, ρ the density of the liquid, g is related to gravity and h the height of the liquid from the marked reference.
The kinetic energy of any moving object is
(1/2) (mass) (speed²) .
For the object you described, that's
(1/2) (100 kg) (12.5 m/s)²
= (50 kg) (156.25 m²/s²)
= 7,812.5 joules
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Your attachment is way out of focus, and impossible to read.
Answer:
The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.
(3) and (4) is correct option.
Explanation:
Given that,
Beat frequency f = 5.0 Hz
Frequency f'= 462 Hz
We need to calculate the possible frequencies for the A string of the other violinist
Using formula of frequency
...(I)
...(II)
Where, f= beat frequency
f₁ = frequency
Put the value in both equations
Hence, The possible frequencies for the A string of the other violinist is 467 Hz and 457 Hz.
Answer:
Explanation:
From the question we are told that:
Weight
Mass of Weight
Generally the acceleration due to gravity on the Moon is one-sixth that on Earth.
Therefore
The equation for Weight on Moon is given as
Explanation:
The figure that accompanies the question shows the wavelenghts of the photons emitted according to Balmer series transition , from energy levels (n) 3, 4, 5, and 6 to the energy level (n) 2, in hydrogen atoms.
These are the values shown in the figure
Transition wavelength of the photon emitted
nm
from n = 3 to n = 2 656 <------------- this is the value requested
from n = 4 to n = 2 486
from n = 5 to n= 2 434
from n = 6 to n = 2 410
The wavelength of a photon emitted from the n = 3 shell in hydrogen is the first data of the table, i.e 656 nm.
Using the conversion factor from nm to m that result is:
656 nm * 1 m / (10^9 nm) = 656 * 10 ^ - 9 m.