Answer:
in the downward movement of the movement when the constant is lost
Explanation:
When the coin is on the piston it has a relationship given by
a = d²x / dt²
the piston position is
x = A cos wt
a = - A w² cos wt
the maximum acceleration is
a = - A w²
When the piston raises the acceleration of gravity and that of the piston go in the same direction, when the piston descends they relate it is contrary to gravity, therefore when the frequency increases, the point where the acceleration of the piston is greater than gravity arrives and the coin loses contact.
The point where you lose contact is
a = g
g = A w²
In short, in the downward movement of the movement when the constant is lost
Decomposers is the correct answer. ( I got your back bro)
Answer:
A pipe open at both ends would have an antinode at each end and its length would be λ/ 2
The next such points would be λ and 3 λ / 2
The ratio of 522 / 348 is 1.5 so the harmonic at 348 is one wavelength and the next harmonic is 3 λ / 2 at 1 1/2 wavelengths
348 hz would occur at one wavelength
f λ = v = f L where the length of the pipe is one wavelength
if we use 331 as the speed of sound then
L = 331 / 348 = .95 m for the length of the pipe
It's the angle made by the incident ray when it's perpendicular to the surface. (Perpendicular lines are the lines that form a graph or like a 90-degree angle)
Explanation:
u = 0m/s
v = 30m/s
a = 2m/s²
Using Kinematics, we have v = u + at.
Therefore t = (v - u) / a
= (30 - 0) / (2) = 15 seconds. (B)
