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yawa3891 [41]
4 years ago
11

Steep and unstable slopes can produce ____________ , forming coarse-grained rocks. magma erupted on the surface can form a _____

_______ that cools quickly, resulting in volcanic glass. some volcanic ash rises vertically in an ____________ , cools before accumulating on the surface, and forms deposits that are pegmatite. some volcanic ash forms ____________ that accumulate while hot and can become ____________ to some extent.
Physics
2 answers:
Ksju [112]4 years ago
8 0

Answer:

Steep and unstable slopes can produce landslides and mud-flows, forming coarse-grained rocks.

Magma erupted on the surface can form a lava flow that cools quickly, resulting in volcanic glass.

Some volcanic ash rises vertically in an eruption column, cools before accumulating on the surface, and forms deposits that are pegmatite.

Some volcanic ash forms pyroclastic flows that accumulate while hot and can become welded to some extent.

Explanation:

The natural instability of the slopes is the reason of the landslides. When the rocks and huge amount of earth move down from a slope, the phenomena is said to be a landslide.

Lava is the molten material which erupts out of a volcano.

During the process of volcanic eruption, the ask which cools down before getting collected is termed to be pegmatite.

On the other hand, pyroclastic is the term used to denote the ash which remains hot at their accumulation.

notka56 [123]4 years ago
6 0

Steep and unstable slopes can produce LANDSLIDES AND MUDFLOWS , forming coarse-grained rocks.  

Landslides occur because of a compromise in the natural stability of a slope. It is characterized by masses of earth and rock rapidly moving down fast in the slant. Mudflows, are also a form of mass wasting attributed by extreme surging flow of liquefied debris and water.

-----------------------------------------------------------------------------------------------------------------

Magma erupted on the surface can form a LAVA FLOW that cools quickly, resulting in volcanic glass.  

Lava flow is a process in volcanic eruptions. Lava flows are oozing streams of molten rock from an erupting vent. Lava runs according to its type and viscosity, steepness of the landscape, whether the lava is flowing as a broad sheet through a tube or channel, and how rapid the production of lava is. When the lava cools immediately, it solidifies without crystallization and becomes a glasslike rock.

-----------------------------------------------------------------------------------------------------------------

Some volcanic ash rises vertically in an ERUPTION COLUMN , cools before accumulating on the surface, and forms deposits that are pegmatite.

Eruption column is emitted during an explosive eruption, as a column or a vertical cloud of ash and tephra in gases. It forms as crystalline granite measuring from several centimeters up to several meters high when it cools before accumulating.

-----------------------------------------------------------------------------------------------------------------

Some volcanic ash forms PYROCLASTIC FLOW that accumulate while hot and can become WELDED to some extent.

Pyroclastic flow is also referred to as pyroclastic density current or pyroclastic cloud. It is tephra as hot as 1000 degrees Celsius, swiftly moving away from the volcano speeding 700 km/h at most. Many pyroclastic flows that are thick become welded—compact and consolidated.


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A block of mass M=10 kg is on a frictionless surface as shown in the photo attached. And it's attached to a wall by two springs
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a.

  • i. the speed of the block of mass when the springs are connected in parallel is 7.07 A m/s
  • ii. the angular velocity when the two springs are in parallel is 7.07 rad/s

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  • i. the speed of the block of mass when the springs are connected in series is 11.2 A m/s
  • ii. the angular velocity when the two springs are in series is 11.2 rad/s

<h3>a. </h3><h3>i. How to calculate the velocity of the mass when the springs are connected in parallel?</h3>

Since k is the spring constant of both springs = 250 N/m. The equivalent spring constant in parallel is k' = k + k

= 2k

= 2 × 250 N/m

= 500 N/m

Now since A is the maximum distance the block is pulled from its equilibrium position, the total energy of the block is E = 1/2kA

Also, 1/2k'A² = 1/2k'x² + 1/2Mv² where

  • k' = equivalent spring constant in parallel = 500 N/m,
  • A = maximum displacement of spring,
  • x = equilibrium position = 0 m,
  • M = mass of block = 10 kg and
  • v = speed of block at equilibrium position

Making v subject of the formula, we have

v = √[k'(A² - x²)/M]

Substituting the values of the variables into the equation, we have

v = √[k'(A² - x²)/M]

v = √[500 N/m(A² - (0)²)/10]

v = √[50 N/m(A² - 0)]

v = [√50]A m/s

v = [5√2] A m/s

v = 7.07 A m/s

So, the speed of the block of mass when the springs are connected in parallel is 7.07 A m/s

<h3>ii. The angular velocity of mass when the springs are in parallel</h3>

Since velocity of spring v = ω√(A² - x²) where

  • ω = angular velocity of spring,
  • A = maximum displacement of spring and
  • x = equilbrium position of spring = 0 m

Making ω subject of the formula, we have

ω = v/√(A² - x²)

Since v = 7.07 A m/s

Substituting the values of the other variables into the equation, we have

ω = v/√(A² - x²)

ω = 7.07 A m/s/√(A² - 0²)

ω = 7.07 A m/s/√(A² - 0)

ω = 7.07 A m/s/√A²

ω = 7.07 A m/s/A m

ω = 7.07 rad/s

So, the angular velocity when the two springs are in parallel is 7.07 rad/s

<h3>b. </h3><h3>i. How to calculate the velocity of the mass when the springs are connected in series?</h3>

Since k is the spring constant of both springs = 250 N/m. The equivalent spring constant in parallel is 1/k" = 1/k + 1/k

= 2/k

⇒ k" = k/2

k" = 250 N/m ÷ 2

= 125 N/m

Now since A is the maximum distance the block is pulled from its equilibrium position, the total energy of the block is E = 1/2kA

Also, 1/2k"A² = 1/2k"x² + 1/2Mv'² where

  • k" = equivalent spring constant in series = 125 N/m,
  • A = maximum displacement of spring,
  • x = equilibrium position = 0 m,
  • M = mass of block = 10 kg and
  • v' = speed of block at equilibrium position

Making v subject of the formula, we have

v = √[k"(A² - x²)/M]

Substituting the values of the variables into the equation, we have

v = √[k"(A² - x²)/M]

v = √[125 N/m(A² - (0)²)/10]

v = √[125 N/m(A² - 0)]

v = [√125]A m/s

v = [5√5] A m/s

v = 11.2 A m/s

So, the speed of the block of mass when the springs are connected in series is 11.2 A m/s

<h3>ii. The angular velocity of the mass when the springs are in series</h3>

Since velocity of spring v = ω√(A² - x²) where

  • ω = angular velocity of spring,
  • A = maximum displacement of spring and
  • x = equilbrium position of spring = 0 m

Making ω subject of the formula, we have

ω = v/√(A² - x²)

Since v = 11.2 A m/s

Substituting the values of the other variables into the equation, we have

ω = v/√(A² - x²)

ω = 11.2 A m/s/√(A² - 0²)

ω = 11.2 A m/s/√(A² - 0)

ω = 11.2 A m/s/√A²

ω = 11.2 A m/s/A m

ω = 11.2 rad/s

So, the angular velocity when the two springs are in series is 11.2 rad/s

Learn more about speed of block of mass here:

brainly.com/question/21521118

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