6 phone numbers are possible for one area code if the first four numbers are 202-1
<u>Solution:</u>
Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order
We have to find how many phone numbers are possible for one area code.
The number of way “n” objects can be arranged is given as n!
Then, we have three places which changes, so we can change these 3 places in 3! ways
Hence 3! is found as follows:
So, we have 6 phone numbers possible for one area code.
Step-by-step explanation:
that is the step by step
brainliest please
7/4 as a mixed number is the mixed number 1 3/4
Answer:
y=0.2x+29
Step-by-step explanation:
Given that:
y is the total monthly of the A Fee and Fee plan.
x is the number of monthly minutes used.
- If a customer uses 290 minutes, the monthly cost will be $87, we have the pair (290, 87)
- If the customer uses 980 minutes, the monthly cost will be $225, this is the coordinate pair (980, 225).
We want to obtain an equation in the form: y=mx+b
First, let us determine the slope, m
Given points (290, 87) and (980, 225):
<u>Slope</u>
Next, we determine the y-intercept, b.
Substituting the pair (290, 87) and m=0.2 in y=mx+b, we obtain
87=0.2(290)+b
b=87-0.2(290)=29
Therefore, our equation in the form y=mx+b is:
y=0.2x+29
Answer:
its none of these answers ;-;
Step-by-step explanation:
3^2 + 8 ÷ 2 - (4 + 3)
we do what's in parentheses first. (pemdas)
so now we have, 3^2 + 8 ÷ 2 - 7
next exponents, 3^2=9
9 + 8 ÷ 2 - 7
next division, 8÷2=4
9 + 4 - 7
next addition, 9+4=13
13-7
finally subtraction, 13-7=6
final answer: 6
