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2 years ago

2C3H7OH + 9O2 -> 6CO2 + 8H2O

Chemistry

1 answer:

MAVERICK [17]2 years ago

6 0

Answer:

Up to $18\; \rm mol$ $\rm CO_2$ .

Explanation:

The equation for this reaction: $2\; \rm C_3 H_7 OH + 9\; O_2 \to 6\; CO_2 + 8\; H_2O$ is indeed balanced.

Notice that the coefficient of $\rm C_3 H_7 OH$ is $2$ while that of $\rm CO_2$ is $6$ .

Therefore, each unit of this reaction would consume $2$ units of $\rm C_3H_7OH$ while producing $6$ units of $\rm CO_2$ . In other words, this reaction would produce three times as much $\rm CO_2\!$ as it consumes $\rm C_3H_7OH\!$ .

If all that $6\; \rm mol$ of $\rm C_3H_7OH$ molecules are actually consumed through this reaction, three times as many $\rm CO_2$ molecules would be produced. That corresponds to $3 \times 6\; \rm mol = 18\; \rm mol$ of $\rm CO_2\!$ molecules.

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An ioc occurs when what metric exceeds its normal bounds?.

IRISSAK [1]

An ionic bond is formed when there are more or less electrons that normal in bonding atoms.

<h3>What are Ionic bonds?</h3>

An ionic bond is formed when one atoms donates electrons to another specie to form an ion pair. One atom is positively charged while the other specie is negatively charged.

Hence, an ionic bond is formed when there are more or less electrons that normal in bonding atoms.

Learn more about ionic bonds: brainly.com/question/14484184

6 0

2 years ago

Arsenic does not have any valence electrons in the 3D orbital because

pogonyaev

Answer:

3d orbital is completely filled.

Explanation:

5 0

3 years ago

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n

Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ= $\frac{-2.18*10^{-18} J}{n^{2} }$

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE= $-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )$

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ= $\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s }{9.1760*10^{-20} J }$

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0

3 years ago

n the 1990’s, the Boeing Co. developed a process for treating wastewater from electroplating and printed circuit board manufactu

scZoUnD [109]

Answer:

Final concentrations:

Cu²⁺ = 0

Al³⁺ = 3.13 mmol/L = 84.51 mg/L

Cu = 4.7 mmol/L = 300 mg/L

Al = 0.57 mmol/L = 15.49 mg/L

Explanation:

2Al (s) + 3Cu²⁺ (aq) → 2Al³⁺ (aq) + 3Cu (s)

Al: 27 g/mol ∴ 100 mg = 3.7 mmol

Cu: 63.5 g/mol ∴ 300 mg = 4.7 mmol

3 mol Cu²⁺ _______ 2 mol Al

4.7 mmol Cu²⁺ _____ x

x = 3.13 mmol Al

4.7 mmol of Cu²⁺ will be consumed.

3.13 mmol of Al will be consumed.

4.7 mmol of Cu will be produced.

3.13 mmol of Al³⁺ will be produced.

0.57 mmol of Al will remain.

6 0

2 years ago

How does a buffer resist change in ph upon addition of a strong acid?

lora16 [44]

Any buffer exists in this equilibrium

HA <=> $H^+ + A^-$
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base ( $A^-$ )

When a strong acid is added, it reacts with the large reservoir of the conjugate base ( $A^-$ ) forming a salt and water. Since this large reservoir of the conjugate base is used, the ph does not alter drastically, but instead resist the pH change.

8 0

3 years ago