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2 years ago

List the three principal states of matter, give two examples of each

Chemistry

1 answer:

icang [17]2 years ago

7 0

matter can take be one of the three states which are; (Solid, Liquid, Gas)

Think about water, it can be a Solid (Ice) a Liquid (not frozen obviously) and a Gas (when it evaporates)

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What does Hess's law state can be done in order to be able to react solid magnesium with oxygen gas safely (that is, without exp

aleksley [76]

Answer:

C. The reaction can be broken down and performed in steps

Explanation:

Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.

To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.

3 0

2 years ago

A solution is made by mixing 33.0 ml of ethanol, C2H6O and 67.0 ml of water. Assuming ideal behavior, what is the vapor pressure

ivann1987 [24]

Grams ethanol = 33 ml times .789 gms/ml = 26.037 gms

Moles ethanol = 26.037 gms / 46 gms/mole = .57 moles 

Moles water = 67 ml or 67 grams/18 gms/mole = 3.22 moles 

total moles = .57 + 3.72 = 4.29 moles 

Mole fraction ethanol = .57 moles ethanol / 4.29 moles total = 0.13

Moles fraction water = 3.72 moles water / 4.29 moles total = 0.87

Partial pressure of ethanol = mole fraction ethanol (.13) _ times VP ethanol 43.9 torr) = 5.707 torr 

partial pressure water = mole fraction water .87) times VP water (l7.5 torr) = 15.23 torr 

Total vapor pressure over solution = 5.71 torr + 15.23 torr = 20.94 torr

7 0

3 years ago

C2952H4664N812O832S8Fe4+NaC4H3O4SAu+Fe(SCN)2+Fe(NH4)2(SO4)2.6H2O+C4H8Cl2S+C8H12MgN2O8=C55H72MgN4+Na4Fe(CN)6+AuSC6H11O5+HClO4+H2S

Scorpion4ik [409]

oh dannnnnnnnnnnnnnnnnnnnnnnnnng XD

7 0

3 years ago

Determine the molarity for each of the following solutions A. 1.8×10^4mg of HCL in 0.075L of solutions

Goryan [66]

The answer would have to be a

4 0

2 years ago

What can you conclude about the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of ye

igor_vitrenko [27]

Answer : The mass of iron(III)sulfide is, 5.4288 g

Solution : Given,

Mass of iron, Fe = 3 g

Mass of sulfur, = 2.5 g

Molar mass of Fe = 56 g/mole

Molar mass of = 256 g/mole

Molar mass of iron(III)sulfide, = 208 g/mole

The balanced chemical reaction is,

First we have to calculate the moles of iron and sulfur.

From the balanced reaction, we conclude that

16 moles of Fe react with 3 moles of

0.054 moles of Fe react with moles of

Therefore, the excess reagent in this reaction is, Fe and limiting reagent is,

Now we have to calculate the moles of FeS.

As, 3 moles of gives 8 moles of

So, 0.0098 moles of gives moles of

The moles of = 0.0261 moles

Now we have to calculate the mass of .

Mass of = Moles of × Molar mass of

Mass of = 0.0261 g × 208 g/mole = 5.4288 g

Therefore, the mass of iron(III)sulfide is, 5.4288 g

Read more on Brainly.com - brainly.com/question/6073920#readmore

5 0

3 years ago