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Law Incorporation [45]
2 years ago
15

Anyone help me please​

Chemistry
1 answer:
SSSSS [86.1K]2 years ago
8 0

Answer:

a person has a duty to use care in dealing with others, and failure to do so is negligence — R. I. Mehr — see also due care, negligence, standard of care.

Explanation:

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The line graph shows the heights of plants grown in fertilized and unfertilized soil. Based on this information, what will most
AfilCa [17]

Answer:

  • <u><em>g) Neither plant should increase by 1 cm in height.</em></u>

Explanation:

See the graph for this question on the figure attached.

The growing of the <em>plant A</em> is represented by the line that goes above the other. At start, that line has a slope that rises about 0.75 cm ( height increase) in 1 day. From the day 2 and forward the slope of the line decreases. The line reaches its highest point about at day 4 and seems to start decreasing. Thus, you should predict that on the day six it <em>most likely </em>does not increase in height.

The growing of the <em>plant B</em> is represented by the line drawn below the other. As for the plant B, the growing decreases with the number of days. Between the days 4 and 5 the line is almost flat, which means that <em>most likely</em> this plant will not grow on the day six or grow less than 0.5 cm.

Thus, for both plants you can say that <em>on day six, most likley, neither should increase by 1 cm in height (</em>option g).

4 0
2 years ago
The elements of which group are nonreactive?
Margaret [11]
The elements of the "Noble" gases group is nonreactive. The reason for this is that noble gases are always or most of the time at room temperature.<span />
3 0
3 years ago
Read 2 more answers
Can someone help me? <br><br>-just check my latest question.. thanks... ​
Harman [31]

Explanation:

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{\boxed{ \fbox{ \fbox{ \fbox{ \green{hello}}}}}}

{\boxed{ \fbox{ \fbox{ \fbox{ \pink{hello}}}}}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{green}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{blue}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{red}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬\mathscr \fcolorbox{blue}{gray}{BE \: BRAINLY}▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

\mathscr \fcolorbox{blue}{pink}{BE \: BRAINLY}

<h2>yes can you. do this</h2>
7 0
2 years ago
Calculate the standard entropy of vaporization of ethanol at its boiling point, 352 K. The standard molar enthalpy of vaporizati
Korvikt [17]

Answer : The correct option is, (b) +115 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{vap}}{T_b}

where,

\Delta S = change in entropy

\Delta H_{vap} = change in enthalpy of vaporization = 40.5 kJ/mol

T_b = boiling point temperature = 352 K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{vap}}{T_b}

\Delta S=\frac{40.5kJ/mol}{352K}

\Delta S=115J/mol.K

Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K

8 0
3 years ago
Mariah needs to identify a cause-and-effect relationship. Which type of investigation should she use?
skad [1K]

Descriptive or Correlational. hope this helps

6 0
3 years ago
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