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alexandr402 [8]
4 years ago
12

Why is it important to have the International System of Units?

Chemistry
1 answer:
omeli [17]4 years ago
4 0
<span>It can be used by scientists everywhere its important to have the International System of Units.</span>
You might be interested in
When Oxygen in the air reacts with Iron, Iron Oxide forms.
Bess [88]

Answer:

I think its E. iron and iron oxide have the same properties if it's not e its d for sure

Explanation:

iron + oxygen → iron oxide. 4 Fe + 3 O2 → 2 Fe2O.

8 0
3 years ago
Which element is larger lithium or bromine
Lera25 [3.4K]
Lithium i think!!
hope this helps
5 0
2 years ago
What is enthalpy in chemistry pls help
Yakvenalex [24]
<span>a thermodynamic quantity representing the unavailability of a system's thermal energy for conversion into mechanical work, often interpreted as the degree of disorder or randomness in the system.</span>
8 0
3 years ago
A steel cylinder for scuba diving contains 11.1 L of compressed air. The pressure inside the cylinder is
Juli2301 [7.4K]

Answer:

9.28moles

Explanation:

Given parameters:

volume  = 11.1L

pressure  = 204atm

temperature  = 24°C = 24 + 273  = 297K

Unknown:

Number of moles of air in the cylinder  = ?

Solution:

To solve this problem, we apply the ideal gas equation;

         PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant  = 0.082atmdm³mol⁻¹K⁻¹

T is the temperature

Now insert the parameters and find n;

     204 x 11.1  = n x 0.082 x 297

    226.4  = 24.4n

        n  = 9.28moles

4 0
3 years ago
A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
6 0
3 years ago
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