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4 years ago

Why is it important to have the International System of Units?

Chemistry

1 answer:

omeli [17]4 years ago

4 0

<span>It can be used by scientists everywhere its important to have the International System of Units.</span>

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A chemist adds of a M copper(II) fluoride solution to a reaction flask. Calculate the mass in micrograms of copper(II) fluoride

anygoal [31]

The question is incomplete, here is the complete question.

A chemist adds 345.0 mL of a 0.0013 mM (MIllimolar) copper(II) fluoride $CuF_2$ solution to a reaction flask.

Calculate the mass in micrograms of copper(II) fluoride the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer : The mass of copper(II) fluoride is, 0.13 mg

Explanation : Given,

Millimolarity of copper (II) fluoride = 0.0013 mM

This means that 0.0013 millimoles of copper (II) fluoride is present in 1 L of solution

Converting millimoles into moles, we use the conversion factor:

1 moles = 1000 millimoles

So, $0.0013mmol\times \frac{1mol}{1000mmol}=1.3\times 10^{-6}mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Moles of copper (II) fluoride solution = $1.3\times 10^{-6}mol$

Molar mass of copper (II) fluoride = 101.5 g/mol

Putting values in above equation, we get:

$1.3\times 10^{-6}mol=\frac{\text{Mass of copper (II) fluoride}}{101.5g/mol}\\\\\text{Mass of copper (II) fluoride}=(1.3\times 10^{-6}mol\times 101.5g/mol)=1.32\times 10^{-4}g$

Converting this into milligrams, we use the conversion factor:

1 g = 1000 mg

So,

$\Rightarrow 1.32\times 10^{-4}g\times (\frac{1000mg}{1g})=0.13mg$

Therefore, the mass of copper(II) fluoride is, 0.13 mg

7 0

3 years ago

Another name for losing electrons is...<br> accepting<br> donating<br> neither

damaskus [11]

The answer is donating. This is because when an atom loses electron, it <em>donates</em> them to another atom.

7 0

3 years ago

A chemical reaction has Hf,reactants = –1,023 kJ and Hf,products = –935.3 kJ. Which graph can be used to represent this reaction

natita [175]

Hey there!

The pathway will resemble a hill , The minimum amount of energy the reagents need to make the complex activated, is the activation energy , The difference in heights of the products and reactants will be equivalent to the difference in energies.:

ΔH = ( -1,023 kj ) - ( - 935,3 kj )

ΔH = -87.7 Kj

7 0

4 years ago

Read 2 more answers

If volume remains the same while the mass of a substance ________, the density of the substance will______________

victus00 [196]

Black and blank sorry idk

4 0

4 years ago

How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?

Nina [5.8K]

11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$