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musickatia [10]
3 years ago
13

Why is the current atomic model called the "electron could model"

Physics
1 answer:
vlada-n [284]3 years ago
8 0
The diagram is showing a 3d model of an atom, with all of the electrons demonstrated in a rounded shape, which resembles a cloud, thus being called an electron cloud.
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An object travels along a straight, horizontal surface with an initial speed of 2 ms. The position of the object as a function o
pashok25 [27]

Answer:

The options are not provided, so i will answer in a general way.

We know that:

The movement is along a straight horizontal surface, then we have one-dimensional motion.

The speed is 2m/s

We want a graph of position vs time.

Now, remember the relation:

Distance = Speed*Time

Then we can write the position as a function of time as:

P(t) = 2m/s*t + P0

Where t is our variable, that represents time in seconds, and P0 is the position at time t = 0seconds, we can assume that this is zero.

Then the equation is:

P(t) = 2m/s*t

And the graph is something like:

3 0
3 years ago
A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force
galina1969 [7]

Answer:

μ =tanθ

Explanation:=

The ratio of the force of static friction and the normal reaction is equal to tanθ. F=mgsinθ. R = mgcosθ.

μ=tanθ

6 0
3 years ago
Read 2 more answers
Drag the correct labels to the images. Each label can be used more than once.
coldgirl [10]

Answer:

plato answer.

Explanation:

4 0
3 years ago
An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic
malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

\omega_f = \omega_0 + \alpha t

Where,

\omega_f =Final Angular Velocity

\omega_0 =Initial Angular velocity

\alpha = Angular acceleration

t = time

The relation between the tangential acceleration is given as,

a = \alpha r

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s

\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s

t = 11s

Replacing the previous equation with our values we have,

\omega_f = \omega_0 + \alpha t

9.8436 = 6.5973 + \alpha (11)

\alpha = \frac{9.8436- 6.5973}{11}

\alpha = 0.295rad/s^2

The tangential velocity then would be,

a = \alpha r

a = (0.295)(0.2)

a = 0.059m/s^2

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

\omega_f^2=\omega_0^2+2\alpha\theta

Replacing with our values and re-arrange to find \theta,

\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}

\theta = \frac{9.8436^2-6.5973^2}{2*0.295}

\theta = 90.461rad

That is equal in revolution to

\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev

The linear displacement of the system is,

x = \theta*(2\pi*r)

x = 14.397*(2\pi*\frac{0.25}{2})

x = 11.3m

5 0
3 years ago
Imagine an alternate universe where all of the quantum number rules were identical to ours except m_{s} had three allowed values
marishachu [46]

Answer:

so in a given orbital there can be 3 electrons.

Explanation:

The Pauli exclusion principle states that all the quantum numbers of an electron cannot be equal, if the spatial part of the wave function is the same, the spin part of the wave function determines how many electrons fit in each orbital.

In the case of having two values, two electrons change. In the case of three allowed values, one electron fits for each value, so in a given orbital there can be 3 electrons.

5 0
3 years ago
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