How much potential energy does a 20-kg barrel have when it is in the truck whose floor is 5.0 m above the ground? P.E. = J
1 answer:
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Answer:
a) Vf = 27.13 m/s
b) It would have been the same
Explanation:
On the y-axis:
Solving for t:
t1 = 0.67s t2= -2.4s
Discarding the negative value and using the positive one to calculate the velocity:
So, the module of the velocity will be:
If you throw it above horizontal, it would go up first, and when it reached the initial height, the velocity would be the same at the throwing instant. And starting then, the movement will be the same.