Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
Hey there!
2Na + Cl₂ → 2NaCl
This is a balanced chemical equation.
There are 2 atoms of sodium (Na) on the left, and 2 atoms of sodium (Na) on the right.
There are 2 atoms of chlorine (Cl) on the left, and 2 atoms of chlorine (Cl) on the right.
This means the equation is balanced since there are the same amount of each element on both sides.
Hope this helps!
C. Carbon tetra–bromide is a non–polar compound, for the four Bromines balance out the dipole moment from the tetrahedral bonds they form on Carbon.
Matter only moves if a force pushes or pulls is true
When the protons and neutrons combine to form a nucleus, the mass that disappears
