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mixer [17]
3 years ago
12

Zn + I2 ---> Znl2 Determine the theoretical yield of the product if 2g of Zn is used

Chemistry
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

Mass = 9.58 g

Explanation:

Given data:

Mass of Zn = 2g

Theoretical yield of ZnI₂ = ?

Solution:

Chemical equation:

Zn + I₂       →     ZnI₂

Number of moles of Zn:

Number of moles = mass/molar mass

Number of moles = 2g / 65.38 g/mol

Number of moles = 0.03 mol

Now we will compare the moles of Zn and ZnI₂.

                   Zn           :          ZnI₂

                    1             :           1

                  0.03        :         0.03

Mass of ZnI₂:

Mass = number of moles × molar mass

Mass = 0.03 mol × 319.22 g/mol

Mass = 9.58 g

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\lambda=241.9\ nm

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So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

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