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2 years ago

The chandra x-ray observatory is used to study _____.

Physics

2 answers:

hjlf2 years ago

5 0

Black holes and images of x-rays

Rainbow [258]2 years ago

3 0

2. Black holes

The Chandra X-ray Observatory (CXO), formally recognized as the Advanced X-ray Astrophysics Facility (AXAF), is a space observatory originated about STS-93 by NASA on July 23, 1999. Chandra is susceptible to X-ray origins 100 times heavier than any preceding X-ray telescope, facilitated by the great angular interpretation of its glasses. Since the Earth's environment receives the vast majority of X-rays, they are not detectable from Earth-based telelectroscope; accordingly space-based telescopes are needed to make these observations. This observatory is basically famous for the study of Black holes in the Universe.

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Answer question 83 and 84

Ne4ueva [31]

83. Gravity is activity as a force on the cart.

84. The box has gathered kinetic energy and momentum and will continue going forward.

6 0

3 years ago

Is the relationship between the length of a pendulum and its period is valid at all times?

Stels [109]

Yes it is valid all the times under the consideration of acceleration due to gravity .it is not valid on space where there is no influence of gravity

4 0

3 years ago

Which type of electromagnetic radiation has the highest frequency?

Likurg_2 [28]

Explanation:

As we know that relation between energy and wavelength is as follows.

E = $\frac{hc}{\lambda}$

This means that energy is inversely proportional to wavelength. So, more is the energy of an electromagnetic radiation less will be its wavelength.

Also, f = $\frac{c}{\lambda}$

Hence, less will be the wavelength more will frequency of a radiation.

Gamma rays are the rays that have highest energy, small wavelength and highest frequency.

Thus, we can conclude that gamma rays are the electromagnetic radiation which has the highest frequency.

7 0

2 years ago

(a) Two ions with masses of 4.39×10^−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic fiel

sammy [17]

Answer:

Part a)

$R_1 = 0.072 m$

Part b)

$R_2 = 0.036 m$

Part c)

d = 0.072 m

Explanation:

Part a)

As we know that the radius of the charge particle in constant magnetic field is given by

$R = \frac{mv}{qB}$

now for single ionized we have

$R_1 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(1.6 \times 10^{-19})(0.301)}$

$R_1 = 0.072 m$

Part b)

Similarly for doubly ionized ion we will have the same equation

$R = \frac{mv}{qB}$

$R_2 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(3.2 \times 10^{-19})(0.301)}$

$R_2 = 0.036 m$

Part c)

The distance between the two particles are half of the loop will be given as

$d = 2(R_1 - R_2)$

$d = 2(0.072 - 0.036)$

$d = 0.072 m$

6 0

2 years ago

A car rounds a curve. The radius of curvature of the road is R, the banking angle with respect to the horizontal is θ and the co

exis [7]

Answer:

v = √[gR (sin θ - μcos θ)]

Explanation:

The free body diagram for the car is presented in the attached image to this answer.

The forces acting on the car include the weight of the car, the normal reaction of the plane on the car, the frictional force on the car and the net force on the car which is the centripetal force on the car keeping it in circular motion without slipping.

Resolving the weight into the axis parallel and perpendicular to the inclined plane,

N = mg cos θ

And the component parallel to the inclined plane that slides the body down the plane at rest = mg sin θ

Frictional force = Fr = μN = μmg cos θ

Centripetal force responsible for keeping the car in circular motion = (mv²/R)

So, a force balance in the plane parallel to the inclined plane shows that

Centripetal force = (mg sin θ - Fr) (since the car slides down the plane at rest, (mg sin θ) is greater than the frictional force)

(mv²/R) = (mg sin θ - μmg cos θ)

v² = R(g sin θ - μg cos θ)

v² = gR (sin θ - μcos θ)

v = √[gR (sin θ - μcos θ)]

Hope this Helps!!!

5 0

2 years ago