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leonid [27]
3 years ago
10

Which type of radiation can reach the furthest? A. Beta B. Gamma C. Alpha

Physics
2 answers:
Mashutka [201]3 years ago
7 0

Answer:

C. Alpha

Explanation:

Gamma radiation, unlike alpha or beta, does not consist of any particles, instead consisting of a photon of energy being emitted from an unstable nucleus. Having no mass or charge, gamma radiation can travel much farther through air than alpha or beta, losing (on average) half its energy for every 500 feet.

kati45 [8]3 years ago
5 0

Answer:

B. Gamma

Explanation:

The gamma radiation can travel much farther through air than alpha or beta.

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The kinetic theory states that the higher the temperature, the faster the
max2010maxim [7]

Answer: the higher the kinetic energy

Explanation:

4 0
3 years ago
A vector is 253m long and points in a 55.8degree direction. Find the y-component of the vector.
kati45 [8]

Answer:

209 m

Explanation:

The y-component of a vector is the magnitude times the sine of the angle.

y = 253 sin 55.8°

y = 209

6 0
3 years ago
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Does distance play a role in the magnetic field ?
OLga [1]
Magnetic force obeys an inverse square law with distance. ... If the distance between two magnets is halved the magnetic force between them will increase to four times the initial value.
8 0
3 years ago
A rock is projected upward from the surface of the moon, at time t = 0.0 s, w a velocity of 30 m/s. The acceleration due to grav
Vinvika [58]
<h2>Answer: 277.777 m</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told that the rock was<u> projected upward from the surface</u>, we will only use the equations related to the Y axis.

In this sense, the movement equations in the Y axis are:

y-y_{o}=V_{o}.t+\frac{1}{2}g.t^{2}    (1)

V=V_{o}-g.t    (2)

Where:

y  is the rock's final position

y_{o}=0  is the rock's initial position

V_{o}=30\frac{m}{s} is the rock's initial velocity

V is the final velocity

t is the time the parabolic movement lasts

g=1.62\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of the moon

As we know y_{o}=0 , equation (2) is rewritten as:

y=V_{o}.t+\frac{1}{2}g.t^{2}    (3)

On the other hand, the maximum height  is accomplished when V=0:

V=V_{o}-g.t=0    (4)

V_{o}-g.t=0    

V_{o}=g.t    (5)

Finding t:

t=\frac{V_{o}}{g}    (6)

Substituting (6) in (3):

y=V_{o}(\frac{V_{o}}{g})+\frac{1}{2}g(\frac{V_{o}}{g})^{2}    (7)

y_{max}=\frac{{V_{o}}^{2}}{2g}    (8)  Now we can calculate the maximum height of the rock

y_{max}=\frac{{(30m/s)}^{2}}{(2)(1.62m/s^{2})}   (9)

Finally:

y_{max}=277.777m  

4 0
3 years ago
A hydraulic turbine is used to generate power by using the water in a dam. The elevation difference between the free surfaces up
Serjik [45]

Answer:

0.906

Explanation:

Let g = 9.81 m/s2. We can calculate the rate of change in potential energy when m = 201kg of water is falling down a distance of h = 131m per second

\dot{E_p} = \dot{m}gh = 201*9.81*131 = 258307 J/s (W) = 258.307 kW

So the efficiency of the water turbine is the ratio of output power over input power:

\frac{234}{258.307} = 0.906

3 0
3 years ago
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