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kirza4 [7]
3 years ago
10

How are mechanical waves and electromagnetic waves alike?

Physics
2 answers:
miss Akunina [59]3 years ago
6 0

I got this answer from the internet

Mila [183]3 years ago
5 0
Answer: Electromagnetic waves can travel through a vacuum; mechanical waves require a medium. Electromagnetic waves are visible; mechanical waves are invisible. Electromagnetic waves always reflect; mechanical waves always refract.




Explanation: There are two types of waves:
Mechanical waves: these waves consist of oscillations of the particles in a medium. Therefore, they can only propagates if there is a medium. Examples of mechanical waves are sound waves
Electromagnetic waves: they consist of oscillations of the electric and the magnetic field in a plane perpendicular to the direction of motion the wave. All electromagnetic waves travel in a vacuum always at the same speed, the speed of light: . They are the only types of waves that do not require a medium to propagate, so they can also travel through a vacuum.
We can now analyze the different statements:
Both types of waves require a medium. --> FALSE. Electromagnetic waves do not require a medium.
Both types of waves have a frequency. --> TRUE. All waves are characterized by their frequency, which is the number of complete oscillations per second.
Both types of waves transmit matter. --> FALSE. Waves transmit energy, but not matter.
Both types of waves have a pitch --> FALSE. Pitch tells how we perceive the frequency of a sound wave: but electromagnetic waves are not sound waves, so this statement is false.
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An insulating cup contains 200 grams of water at 25 ∘C. Some ice cubes at 0 ∘C is placed in the water. The system comes to equil
Nataly [62]

Answer:

The amount of ice added in gram is 32.77g

Explanation:

This problem bothers on the heat capacity of materials

Given data

Mass of water Mw= 200g

Temperature of water θw= 25°c

Temperature of ice θice= 0°c

Equilibrium Temperature θe= 12°c

Mass of ice Mi=???

The specific heat of ice Ci= 2090 J/(kg ∘C)

specific heat of water Cw = 4186 J/(kg ∘C)

latent heat of the ice to water transition Li= 3.33 x10^5 J/kg

heat heat loss by water = heat gained by ice

N/B let us understand something, heat gained by ice is in two phases

Heat require to melt ice at 0°C to water at 0°C

And the heat required to take water from 0°C to equilibrium temperature

Hence

MwCwΔθ=MiLi +MiCiΔθ

Substituting our data we have

200*4186*(25-12)=Mi*3.3x10^5+

Mi*2090(12-0)

837200*13=Mi*3.3x10^5+Mi*2090

10883600=332090Mi

Mi=10883600/332090

Mi= 32.77g

4 0
3 years ago
In an energy pyramid, the total energy available for consumption from one trophic level to the next one it is
Flura [38]

Answer: Conserved

Explanation:

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3 years ago
The park has added two more cars to the already existing roller coaster. If the park wants to maintain the speed of the roller c
vredina [299]
D because friction will slow it down going up hills (for safety reasons) and you go really fast going down.
7 0
3 years ago
Read 2 more answers
In a closed system, _____ energy is equal to potential energy plus kinetic energy.
OlgaM077 [116]
The answer would be "mechanical". Hope I helped. :)
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3 years ago
How far from Earth must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances
Tatiana [17]

Answer:

258774.9441 m

Explanation:

x = Distance of probe from Earth

y = Distance of probe from Sun

Distance between Earth and Sun = x+y=149.6\times 10^6\ m

G = Gravitational constant

M_s = Mass of Sun = 1.989\times 10^{30}

M_e = Mass of Earth = 5.972\times 10^{24}\ kg

According to the question

\frac{GM_sm}{x^2}=\frac{GM_em}{y^2}\\\Rightarrow \frac{M_s}{x^2}=\frac{M_e}{y^2}\\\Rightarrow x=\sqrt{\frac{M_s\times y^2}{M_e}}\\\Rightarrow x=\sqrt{\frac{1.989\times 10^{30}\times y^2}{5.972\times 10^{24}}}\\\Rightarrow x=577.10852y

x+y=149.6\times 10^6\\\Rightarrow 577.10852y+y=149.6\times 10^6\\\Rightarrow 578.10852y=149.6\times 10^6\\\Rightarrow y=\frac{149.6\times 10^6}{578.10852}\\\Rightarrow y=258774.9441\ m

The probe should be 258774.9441 m from Earth

7 0
3 years ago
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