How are mechanical waves and electromagnetic waves alike?

Physics

2 answers:

miss Akunina [59]3 years ago

6 0

I got this answer from the internet

Mila [183]3 years ago

5 0

Answer: Electromagnetic waves can travel through a vacuum; mechanical waves require a medium. Electromagnetic waves are visible; mechanical waves are invisible. Electromagnetic waves always reflect; mechanical waves always refract.

Explanation: There are two types of waves:
Mechanical waves: these waves consist of oscillations of the particles in a medium. Therefore, they can only propagates if there is a medium. Examples of mechanical waves are sound waves
Electromagnetic waves: they consist of oscillations of the electric and the magnetic field in a plane perpendicular to the direction of motion the wave. All electromagnetic waves travel in a vacuum always at the same speed, the speed of light: . They are the only types of waves that do not require a medium to propagate, so they can also travel through a vacuum.
We can now analyze the different statements:
Both types of waves require a medium. --> FALSE. Electromagnetic waves do not require a medium.
Both types of waves have a frequency. --> TRUE. All waves are characterized by their frequency, which is the number of complete oscillations per second.
Both types of waves transmit matter. --> FALSE. Waves transmit energy, but not matter.
Both types of waves have a pitch --> FALSE. Pitch tells how we perceive the frequency of a sound wave: but electromagnetic waves are not sound waves, so this statement is false.

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A power plant produces 1000 MW to supply a city 40 km away. Current flows from the power plant on a single wire of resistance 0.

nikitadnepr [17]

Answer:

Current = 8696 A

Fraction of power lost = $\dfrac{80}{529}$ = 0.151

Explanation:

Electric power is given by

$P=IV$

where I is the current and V is the voltage.

$I=\dfrac{P}{V}$

Using values from the question,

$I=\dfrac{1000\times10^6 \text{ W}}{115\times10^3\text{ V}} = 8696 \text{ A}$

The power loss is given by

$P_\text{loss} = I^2R$

where R is the resistance of the wire. From the question, the wire has a resistance of $0.050\Omega$ per km. Since resistance is proportional to length, the resistance of the wire is