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mariarad [96]
3 years ago
13

A swimming pool has the shape of a box with a base that measures 21 m by 14 m and a depth of 3.1 m. how much work is required to

pump the water out of the pool when it is? full? use 1000 kg divided by m cubed for the density of water and 9.8 m divided by s squared for the acceleration due to gravity.
Physics
1 answer:
Lynna [10]3 years ago
5 0
The work needed to pump the water would have the units of Joules or Pa*m^3. From here, this would be a hint that you only multiply the hyraulic pressure and its volume.

Hydraulic pressure = density*gravity*height = 1000*9.8*3.1 = 30,411 Pa
Volume = 21*14*3.1 = 911.4 m^3
Work = 30,411*911.4 = 27,716,585.4 J = 27.72 MJ
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A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci
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Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

\vec v_1=(x_1,y_1)

\vec v_2=(x_2,y_2)

The sum of the vectors is:

\vec v=(x_1+x_2,y_1+y_2)

The magnitude of a vector can be calculated by

d=\sqrt{x^2+y^2}

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

\vec v_1=(-34,0)

The wind blows at 19 m/s south, thus:

\vec v_2=(0,-19)

The sum of both velocities gives the resultant velocity:

\vec v =(-34,-19)

The magnitude of this velocity is:

d=\sqrt{(-34)^2+(-19)^2}

d=\sqrt{1156+361}=\sqrt{1517}

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

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