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rusak2 [61]
3 years ago
8

How does Newton's second law apply to the egg drop?

Physics
1 answer:
avanturin [10]3 years ago
4 0
<span> Newtons First Law is applied on my egg experiment because it will not move or change it's acceleration until a force acts upon it. In this case, one example of those forces would be Mr. Baker picking up the egg project. Newton's Second Law is applied because of the acceleration caused by natural forces as the egg is plummeting to the earth.</span>
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The masses of the earth and moon are 5.98 x 1024 and 7.35 x 1022 kg, respectively. Identical amounts of charge are placed on eac
dybincka [34]

Answer:

The magnitude of charge on each is 5.707\times 10^{13} C

Solution:

As per the question:

Mass of Earth, M_{E} = 5.98\times 10^{24} kg

Mass of Moon, M_{M} = 7.35\times 10^{22} kg

Now,

The gravitational force of attraction between the earth and the moon, if 'd' be the separation distance between them is:

F_{G} = \frac{GM_{E}M_{M}}{d^{2}}        (1)

Now,

If an identical charge 'Q' be placed on each, then the Electro static repulsive force is given by:

F_{E} = \frac{1}{4\pi\epsilon_{o}}\frac{Q^{2}}{d^{2}}           (2)

Now, when the net gravitational force is zero, the both the gravitational force and electro static force mut be equal:

Equating eqn (1) and (2):

\frac{GM_{E}M_{M}}{d^{2}} = \frac{1}{4\pi\epsilon_{o}}\frac{Q^{2}}{d^{2}}

(6.67\times 10^{- 11})\times (5.98\times 10^{24})\times (7.35\times 10^{22}) = (9\times 10^{9}){Q^{2}}

\sqrt{\farc{(6.67\times 10^{- 11})\times (5.98\times 10^{24})\times (7.35\times 10^{22})}{9\times 10^{9}}} = Q

Q = \pm 5.707\times 10^{13} C

7 0
3 years ago
Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f
Sergeu [11.5K]

Answer:

f = 55mm,     h ’= -9.89 cm

f = 200 mm,  h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

         \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

         \frac{1}{q_1} = \frac{1}{0.55} - \frac{1}{10}

          \frac{1}{q_1} = 1.718

          q₁ = 0.582 m

lens with f₂ = 200mm = 2m

           \frac{1}{q_2} =   \frac{1}{2} - \frac{1}{10}

            \frac{1}{q_2} = 0.4

            q₂ = 2.5 m

the magnification of a lens is given by

            m = \frac{h'}{h} = -  \frac{q}{p}

             h ’= - \frac{q}{p} \ h

let's calculate for each lens

f = 55mm

             h '= - 0.582 / 10 1.7

             h ’= 0.0989 m

             h ’= -9.89 cm

f = 200 mm

             h '= - 2.5 / 10 1.7

             h ’= -0.425 m

             h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0
3 years ago
Seismic waves carry energy from earthquakes through the earth's crust. Seismic waves are...
Crank

Answer:

- longitudinal waves only

Explanation:

The P seismic waves travel as elastic motions at the highest speeds. They are longitudinal waves that can be transmitted by both solid and liquid materials in the Earth's interior.

3 0
3 years ago
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Phoenix [80]
There are 3 states of matter. Solid, Liquid, Gas. An example of each would be ice, water, steam,
5 0
2 years ago
Spaceship A moves at 0.800 in the positive - direction, while spaceship B moves in the opposite direction at 0.750 (both speeds
Eva8 [605]

Explanation:

Spaceship A moves at 0.800 in the positive – direction, while spaceship B moves in the opposite direction at 0.750 (both speeds are measured relative to Earth). What is the velocity {A,B} of spaceship A relative to spaceship B

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