Answer:
The rate at which the electric field changes between the round plates of a capacitor is .
Explanation:
It is given in the problem that the round plates of a capacitor are spaced some distance apart and the voltage across them is changing.
The expression for the electric field in terms of voltage is as follows;
Here, E is the electric field, V is the voltage and d is the distance of separation.
Differentiate expression of the electric field with respect to time, t.
Convert the distance of separation from mm to m.
d= 1.2 mm
Calculate the rate at which the electric field changes.
Put and
Therefore, the rate at which the electric field changes is .
Explanation:
Given that,
Number of turns in the coil, N = 100
Area of the coil, A = 100 cm² = 0.01 m²
It is placed at an angle of 70°.
Magnetic field, B = 0.1 Wb/m²
We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.
Magnetic flux is given by :
So, the magnetic flux through the coil is 0.1 Wb.
Emf induced in the coil is :
So, 34V of emf is induced in the coil.
Potential difference= current x resistance
so current = potential difference÷resistance
current =3÷120 (two bulbs 60+60)
current =0.025A
Since you did not enumerate the features to choose from, I'll just give you a brief information about acidic water.
>Acidic water<span> has a pH below 7 or less than 7.0.
</span>> Acidic water can dissolve a limestone rock.
> The <span>land features which are formed in limestone by reaction with acid water are the stalactites and the stalagmites.</span>