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scoundrel [369]
4 years ago
13

Use the small-angle formula to calculate the angular diameter of Earth as seen from the Moon. (Note: The linear diameter of Eart

h is ; the average distance between the Moon and Earth is ; the small-angle formula is .)
Physics
1 answer:
Sedaia [141]4 years ago
4 0

Answer: 1.90°

Explanation:

The small angle formula is given as:

tanθ = D/d

Where

θ = angular diameter;

D = diameter of the earth;

d = distance from moon to the earth.

Therefore, angular diameter, θ, is:

θ = tan⁻¹(D/d)

The (equatorial) diameter of the earth, D, is 12756.2km.

The mean distance of the moon from the earth, d, is 384399km.

Hence,

θ = tan⁻¹(12756.2/384399)

θ = tan⁻¹(0.03318478976272)

θ = 1.90°

Hence, the angular diameter of the earth, using the small angle formula, is 1.90°.

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A vehicle has an initial velocity of v0 when a tree falls on the roadway a distance xf in front of the vehicle. The driver has a
Korvikt [17]

Answer:

v^2=v_o^2-2\times a\times (v_o.t)

Explanation:

Given:

Initial velocity of the vehicle, v_o

distance between the car and the tree, x_f

time taken to respond to the situation, t

acceleration of the car after braking, a

Using equation of motion:

v^2=u^2+2a.s ..............(1)

where:

v= final velocity of the car when it hits the tree

u= initial velocity of the  car when the tree falls

a= acceleration after the brakes are applied

s= distance between the tree and the car after the brakes are applied.

s=v_o\times t

Now for this situation the eq. (1) becomes:

v^2=v_o^2-2\times a\times (v_o.t) (negative sign is for the deceleration after the brake is applied to the car.)

5 0
3 years ago
A race car's velocity increases from +28 m/s to +36 m/s over a 2.0-s time interval. What is the car's
BigorU [14]

Answer:

4 m/s^{2}

Explanation:

Acceleration, a=\frac {v-u}{t}

Where v and u are the final and initial velocities of the race car respectively, t is the time taken for the race car to attain velocity of 36 m/s.

Substituting 36 m/s for v, 28 m/s for u and 2 s for t then

a=\frac {36 m/s-28 m/s}{2}=4 m/s^{2}

3 0
3 years ago
How do we know the age of the canyon diablo meteorite ?
Nostrana [21]

Answer:

how ever many layers it has i think

Explanation:

4 0
3 years ago
A circular loop of flexible iron wire has an initial circumference of 164cm , but its circumference is decreasing at a constant
Travka [436]

Answer:

emf = 0.02525 V

induced current with a counterclockwise direction

Explanation:

The emf is given by the following formula:

emf=-\frac{\Delta \Phi_B}{\Delta t}=-B\frac{\Delta A}{\Delta t}\ \ =-B\frac{A_2-A_1}{t_2-t_1}   (1)

ФB: magnetic flux =  BA

B: magnitude of the magnetic field = 1.00T

A2: final area of the loop; A1: initial area

t2: final time, t1: initial time

You first calculate the final A2, by taking into account that the circumference of loop decreases at 11.0cm/s.

In t = 4 s the final circumference will be:

c_2=c_1-(11.0cm/s)t=164cm-(11.0cm/s)(4s)=120cm

To find the areas A1 and A2 you calculate the radius:

r_1=\frac{164cm}{2\pi}=26.101cm\\\\r_2=\frac{120cm}{2\pi}=19.098cm

r1 = 0.261 m

r2 = 0.190 m

Then, the areas A1 and A2 are:

A_1=\pi r_1^2=\pi (0.261m)^2=0.214m^2\\\\A_2=\pi r_2^2=\pi (0.190m)^2=0.113m^2

Finally, the emf induced, by using the equation (1), is:

emf=-(1.00T)\frac{(0.113m^2)-(0.214m^2)}{4s-0s}=0.0252V=25.25mV

The induced current has counterclockwise direction, because the induced magneitc field generated by the induced current must be opposite to the constant magnetic field B.

4 0
3 years ago
A certain rain cloud at an altitude of 1.80 km contains 3.20 107 kg of water vapor. How long would it take for a 2.90-kW pump to
kvasek [131]

Answer:

2255 days

Explanation:

height, h = 1.8 km = 1800 m

amount of water, m = 3.2 x 10^7 kg

Power, P = 2.9 kW = 2900 W

Let t be the time taken

Energy required to lift the water,

E = m g h

E = 3.2 x 10^7 x 9.8 x 1800 = 5.65 x 10^11 J

Power, P = Energy / time

t = E / P = (5.65 x 10^11) / 2900

t = 1.95 x 10^8 second

t = 2255 days

thus, the time taken is 2255 days.

7 0
4 years ago
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