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NNADVOKAT [17]
3 years ago
15

A race car's velocity increases from +28 m/s to +36 m/s over a 2.0-s time interval. What is the car's

Physics
1 answer:
BigorU [14]3 years ago
3 0

Answer:

4 m/s^{2}

Explanation:

Acceleration, a=\frac {v-u}{t}

Where v and u are the final and initial velocities of the race car respectively, t is the time taken for the race car to attain velocity of 36 m/s.

Substituting 36 m/s for v, 28 m/s for u and 2 s for t then

a=\frac {36 m/s-28 m/s}{2}=4 m/s^{2}

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An object at rest is suddenly broken apart into fragments a and b by an explosion. the fragment a acquires three times the kinet
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<span> Given that the fragment a acquires three times the kinetic energy of the fragment b.  
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P</span><span><span>initial </span><span>= p</span></span>final ⇒ 0 =mₐv⁰ₐ+mьv⁰ь= 0 ⇒ v⁰ь = -mₐv⁰ₐ/mь

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4 0
4 years ago
Calculate the angular velocity of a clocks second hand, its minute hand, and its hour hand. State in Rad/s. What is its angular
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Hour hand:

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