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-Dominant- [34]
3 years ago
14

A 25.0 mL sample of a solution of an unknown compound is titrated with a 0.115 M NaOH solution. The titration curve above was ob

tained with pH at equivalence point of around 8. The unknown compound is ________.
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
3 0

Answer:

Weak acid

Explanation:

A titration curve is a graphical description of the change in pH of the solution in the conical flask as the reagent is added from the burette. A titration curve can be plotted for the different kinds of acid and base titrations. The volume of the titrant is always plotted as the independent variable and the pH of the solution as the dependent variable. The equivalence point is read off from the titration curve. A titration curve is very important because it shows the pH at various points during the titration.

A weak acid/strong base titration leads to an equivalence point above 7. From the question, we were told that the pH at equivalence point lies around 8. Hence the unknown substance must be a weak acid.

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water is formed when 48g of oxygen combine with 6g of hydrogen. what mass of oxygen combines with 2g of hydrogen
Mariulka [41]

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16g of oxygen reacts with 2 g of hydrogen to form 18g of Water

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Where do food molecules for cecropia trees come from?
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Answer:

Central and South American forests.

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2 years ago
Which property of sulphuric acid makes it suitable to use as a catalyst for the preparation of esters?​
lions [1.4K]
In Fisher esterification, sulfuric acid is used as a catalyst and its function is to convert the carboxylic compound in its conjugate acid. This favours the nucleophilic attack of the alcohol. To act as a catalyst you need a strong acid, therefore sulphuric acid is suitable for this kind of reaction.
3 0
2 years ago
Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g
Charra [1.4K]

Answer:

4.71 g of sodium and 7.25 g of chlorine

Explanation:

<em>Note: The question is incomplete. the complete question is given below:</em>

<em>Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?</em>

<em>4.71 g of sodium and 3.30 g of chlorine</em>

<em>4.71 g of sodium and 7.25 g of chlorine</em>

<em>4.71 g of sodium and 1.31 g of chlorine</em>

<em>4.71 g of sodium and 13.7 g of chlorine</em>

The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.

This means that irrespective of the source of any sample of a pure chemical compound, the constituents elements are always combined in the same mass ratio.

In the first sample, the mass ratio of Sodium to chlorine is given below:

mass of sodium = 2.55 g

mass of chlorine = 3.93 g

mass ratio; sodium to chlorine = 2.55 / 3.93 = 0.65

From the set of masses give above, we can determine the result of the decomposition of the second sample.

4.71 g of sodium and 3.30 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 3.30 = 1.43

4.71 g of sodium and 7.25 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 7.25 = 0.65

4.71 g of sodium and 1.31 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 1.31 = 3.59

4.71 g of sodium and 13.7 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 13.7 = 0.34

From the results above, the correct set of masses for the second sample is 4.71 g of sodium and 7.25 g of chlorine

3 0
2 years ago
The vapor pressure of pure pentane and pure hexane are 425 torr and 151 torr respectively. equal moles of pentane and hexane are
nadezda [96]

The mole fraction of pentane in the vapor is 0.291

Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Using the formula for vapour pressure,

vapour pressure = P^{}°_{hex} × X_{hex} + P^{}°_{pen} × X_{pen}

vapour pressure = 151 ×  (1-X_{pen}) + 425 × X_{pen}

240 = 151 - 151X_{pen} + 425X_{pen}

240 - 151 = -  151X_{pen} + 425 X_{pen}

89 = 274 X_{pen}

\frac{89}{274} = X_{pen}

0.291 = X_{pen}

Therefore,  the mole fraction of pentane in the vapor is 0.291

Learn more about vapour pressure here;

brainly.com/question/25699778

#SPJ4

3 0
1 year ago
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