Heat required to raise 1 g of a substance 1°C

maks197457 [2]

Answer:

I would put, A substance has two different parts of it, a pure substance and a compound and mixtures have two as well called, homogenous mixtures and hetrogeneous mixtures.

Explanation:

7 0

3 years ago

What is a layer of solid of the solid earth

nikitadnepr [17]

The answer is The mantle

6 0

3 years ago

Only_________are involved in forming chemical bonds betwen two atoms

olchik [2.2K]

C)

Only valence electrons are involved in forming chemical bonds betwen two atoms.

Hope this helped you- have a good day bro cya)

4 0

2 years ago

Calcula la cantidad de gramos que hay en 12,5 mol de NaCl (Masa Na: 23,0; Cl: 35,5).

Anon25 [30]

Answer:

731.25 g

Explanation:

The question asks us to calculate the mass of 12.5 moles of NaCl. The individual relative atomic masses of the elements were supplied. We must first obtain the molar mass of sodium chloride as follows;

Molar mass of sodium chloride= 23.0 + 35.5 = 58.5 gmol-1

From the formula;

Number of moles (n) = mass /molar mass

Number of moles of sodium chloride= 12.5 moles

Mass of sodium = The unknown

Molar mass of sodium chloride= 58.5gmol-1

Mass of sodium chloride= number of moles × molar mass

Mass of sodium chloride= 12.5 × 58.5

Mass of sodium chloride= 731.25 g

4 0

3 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.
C is the specific heat substance.
ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

Mass of metal = 50 g
Initial temperature of metal= 45 °C
Final temperature of metal= 11.08 ºC
Specific heat of metal= ?

For water:

Mass of water = 250 g
Initial temperature of water= 10 ºC
Final temperature of water= 11.08 ºC
Specific heat of water = 1.035 $\frac{cal}{gC}$

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 $\frac{cal}{gC}$ × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= $\frac{279.45 cal}{1696 gC}$