Answer:
53.7 grams of HNO3 will be produced
Explanation:
Step 1: Data given
Mass of NO2 = 59.0 grams
Molar mass NO2 = 46.0 g/mol
Step 2: The balanced equation
3NO2 + H2O→ 2HNO3 + NO
Step 3: Calculate moles NO2
Moles NO2 = 59.0 grams / 46.0 g/mol
Moles NO2 = 1.28 moles
Step 4: Calculate moles HNO3
For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO
For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3
Step 7: Calculate mass HNO3
Mass HNO3 = 0.853 moles * 63.01 g/mol
Mass HNO3 = 53.7 grams
53.7 grams of HNO3 will be produced
Answer:
Water pressure 0.5 atm
Total Pressure= 2.27 atm
Explanation:
To answer this problem, one has to realize that there are two processes that increase the temperature of the sealed vessel.
First, the dry air in the sealed vessel will be heated which will cause its pressure to increase and it can be determined by the equation:
P₁ x T₂ = P₂ x T₁ ∴ P₂ = P₁ x T₂ / T₁
For the second process, we have an amount of n moles of water which will be released when the copper sulfate is heated. In this case, to determine the value of the the water gas we will use the gas law:
PV = nRT ∴ P = nRT/V
n will we calculated from the quantity of sample.
2.50 g CuSo₄ 5H₂O x 1 mol/ 249.69 g = 0.01 mol CuSo₄ 5H₂O
the amount water of hydration is
= 0.01 mol CuSo₄ 5H₂O * 5 mol H₂O / 1 mol CuSo₄ 5H₂O
= 0.05 mo H₂O
pressure of dry air at the final temperature,
P₂ = 1 atm x 500 K/ 300 K = 1.67 atm
Pressure of water :
P (H₂O) 0.05 mol x 0.08206 Latm/kmol x 500 K/ 4 L = 0.5 atm
∴ Total Pressure = 1.67 atm
H2O Pressure = 0.5 atm
Answer:
H₂SO₄
Explanation:
Given data:
Number of moles of H₂SO₄ = 15 mol
Number of moles of Fe = 13 mol
Which reactant is limiting reactant = ?
Solution:
Chemical equation:
3H₂SO₄ + 2Fe → Fe₂(SO₄)₃ + 3H₂
now we will compare the moles reactant with product.
H₂SO₄ : Fe₂(SO₄)₃
3 : 1
15 : 1/3×15 = 5
H₂SO₄ : H₂
3 : 3
15 : 15
Fe : Fe₂(SO₄)₃
2 : 1
13 : 1/2×13 = 6.5
Fe : H₂
2 : 3
13 : 3/2×13 = 19.5
Number of moles of product formed by H₂SO₄ are less thus it will act as limiting reactant.
Considering the definition of mass volume percentage, the percent concentration of dextrose is 45%.
<h3>Mass volume percentage</h3>
Mass volume percentage (% m/V) is a measure of concentration that indicates the number of grams of solute per 100 volume units of the solution. In other words, the volume percent of a component in the solution is defined as the ratio of the mass of the component to the volume of the solution, expressed as a percentage.
The mass volume percentage of a solution is determined by the following expression:

<h3>Percent concentration in this case</h3>
In this case, you know:
- mass of solute= 450 grams
- volume of solution= 1 L= 1000 mL
Replacing in the definition of mass volume percentage:

Solving:
<u><em>mass volume percentage= 45%</em></u>
Finally, the percent concentration of dextrose is 45%.
Learn more about mass volume percentage:
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Answer: e. All voltaic (galvanic) cells involve the use of electricity to initiate nonspontaneous chemical reactions.
Explanation:
Electrochemical cell or galvanic cell or voltaic cell is a cell which converts chemical energy to electrical energy.
There are two electrodes in an electrochemical cell , where one is called as anode and one is called as cathode.
At cathode reduction takes place and at anode oxidation takes place.Thus the electrons generated at anode travel towards cathode and flow of electrons lead to generation of electricity.
Thus chemical reactions lead to generation of electricity.
Thus the statement that all voltaic cells involve the use of electricity to initiate nonspontaneous chemical reactions is false.