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ale4655 [162]
3 years ago
14

Help would be greatly appreciated:) thank you! a pendulum clock is brought to mars. How does the bob move on Mars as compared to

on earth? a. it runs slower b. it keeps time just as on earth c. the effect depends on the amplitude of the swing d. it runs faster
Physics
1 answer:
Alborosie3 years ago
8 0
It runs slower <span>as gravity is lower so acceleration due to gravity is smaller</span>
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Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite
ikadub [295]

Answer:

  R = 6.3456 10⁴  mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

      F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

      a = v² / r

Where the distance is taken from the center of the Earth

     G m M / r² = m v² / r

     G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

     d = 2π  r

     v = d / t

The time for a full turn is called period (T)

Let's replace

     G M / r = (2π r / T)²

     r³ = G M T²²2 / 4π²

     r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

      T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

      Re = 6.37 10⁶ m

Let's calculate

     r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

     r = ∛ (1.027487 10²⁴)

     r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

     R = r - Re

     R = 108.47 10⁶ - 6.37 10⁶

     R = 102.1 10⁶ m

Let's reduce to miles

      R = 102.1 10⁶ m (1 mile / 1609 m)

     

      R = 6.3456 10⁴  mile

6 0
3 years ago
When is an object moving in uniform circular motion?
ad-work [718]
When its tangential speed is constant
<span>Although the speed of an object that has a uniform circular motion is constant, its velocity is </span>not constant<span>. Not only that, but it is actually changing constantly.</span><span>

</span>
6 0
4 years ago
Read 2 more answers
1) Halving the distance (i.s., decreasing by a factor of two) between two charged objects will cause the electrical force betwee
Vedmedyk [2.9K]

Answer:

Explanation:

For an electric force, F the formula:

F = kQq/r^2

Given:

r2 = 1/2 × r1

F1 × r1 = k

F1 × r1 = F2 × r2

F2 = (F1 × r1^2)/(0.5 × r1)^2

= (F1 × r1^2)/0.25r1^2

= 4 × F1.

7 0
4 years ago
According to the "Law of Increasing Opportunity Costs," what would be the opportunity cost of a student who is staying up all ni
kodGreya [7K]

C. The opportunity cost of a student who is staying up all night to study for an exam that he has to take in the early morning is sleep or rest.

<h3>What is law of opportunity cost?</h3>

The law of increasing opportunity cost is an economic principle that describes how opportunity costs increase as resources are applied.

As the student gives up his sleep or night rest in the place of his exam preparation, we say that the opportunity cost is the sleep or rest.

Thus, the opportunity cost of a student who is staying up all night to study for an exam that he has to take in the early morning is sleep or rest.

Learn more about opportunity cost here: brainly.com/question/8846809

#SPJ1

7 0
2 years ago
You own a yacht which is 14.5 meters long. It is motoring down a canal at 10.6 m/s. Its bow (the front of the boat) is just abou
Alex73 [517]

Answer:

4.198 seconds

Explanation:

The total length of the yacht is 30m and the width of the bridge is 14.5m.

The speed of the yacht is 10.6m/s.

We can assume the current of the canal has a speed of 0m/s.

To calculate the answer we will break it into two parts

1) The time it takes for the bow to travel from the start of the bridge to the end

<em>Formula Speed = Distance / Time</em>

Speed = 10.6m/s

Distance = 30m

Time = T1

T1 = 2.8301s

2) The time it takes for the stern to cross the end of the bridge after the bow

<em />

<em>Formula Speed = Distance / Time</em>

<em />

Speed = 10.6m/s

Distance = 14.5m

Time = T2

T2 = 1.3679s

3) The Total Time is

Total = T1 + T2

Total = 4.198s

5 0
3 years ago
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