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Firlakuza [10]
2 years ago
9

A 3.00-kg object has a velocity 1 6.00 i ^ 2 2.00 j ^2 m/s. (a) what is its kinetic energy at this moment? (b) what is the net w

ork done on the object if its velocity changes to 1 8.00 i ^ 1 4.00 j ^
Physics
1 answer:
tatyana61 [14]2 years ago
7 0
(a) The velocity of the object on the x-axis is 6 m/s, while on the y-axis is 2 m/s, so the magnitude of its velocity is the resultant of the velocities on the two axes:
v= \sqrt{(6.00m/s)^2+(2.00 m/s)^2}=6.32 m/s
And so, the kinetic energy of the object is
K= \frac{1}{2}mv^2= \frac{1}{2}(3.00 kg)(6.32 m/s)^2=60 J

(b) The new velocity is 8.00 m/s on the x-axis and 4.00 m/s on the y-axis, so the magnitude of the new velocity is
v= \sqrt{(8.00 m/s)^2+(4.00 m/s)^2}=8.94 m/s
And so the new kinetic energy is
K= \frac{1}{2}mv^2= \frac{1}{2}(3.00 kg)(8.94 m/s)^2=120 J

So, the work done on the object is the variation of kinetic energy of the object:
W=\Delta K=120 J-60 J=60 J
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If a wave has a wavelength of 9 meters and a period of 0.006, what is the velocity of the wave?
lana66690 [7]

<u>Answer</u>

D. 1,500 m/s

<u>Explanation</u>

the wave equation states that,

V = λf

Where V ⇒ Velocity

λ ⇒ wavelength

f ⇒ Frequency

F = 1/T

Where T ⇒ period

F = 1/0.006

= 166.667

∴ V = 9 × 166.667

= 1,500 m/s

4 0
3 years ago
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which of the following are good conductors under normal conditions? A. Penny B.copper wire C. a dime D.plastic E.aluminum foil F
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Answer:

see explanation

Explanation:

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3 years ago
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The basic barometer can be used to measure the height of a building. If the barometric readings at the top and at the bottom of
LekaFEV [45]

Answer:

   (h₁-h₂) = 2.30 10² m

Explanation:

The pressure depends on the height with the formula

          P = P_atm + rho g h

Let's apply this expression for the building

         P₁ = P_atm + rho_air g h₁

        P₂ = P_atm + rho_air g h₂

Subtract

        P₁ - P₂ = roh_air g (h₁ –h₂)

         

         

The measured pressure is in mm Hg to take this unit to units of pressure must be multiplied by the density of mercury and the acceleration of gravity

           P₁- P₂ = rho_Hg g (h₁-h₂) _Hg

         rho_Hg g (h₁-h₂) _Hg = roh_air g (h₁ –h₂)

          (h₁ –h₂) = rho_Hg / rho_air (h₁-h₂) _ Hg

Let's calculate

         (h₁-h₂) = 13600 / 1.18 (695-675)

         (h₁-h₂) = 2.30 10⁵ mm

Let's reduce to meter

         (h₁-h₂) = 2.30 10⁵ mm (1 m / 10³ mm)

         (h₁-h₂) = 2.30 10² m

4 0
3 years ago
What part of the body acts as levelers
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Answer: your feet are the foundation! Even though all your body parts are connected and affect one another, your feet are what we at Foot Levelers call, the "foundation".

Explanation:

3 0
2 years ago
Pls help me i need both answers pls help me this is being timed.
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Answer:

it would have to be diagram C OR B

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