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Fittoniya [83]
3 years ago
15

What is 15=-3y+21x in slope intercept form?

Mathematics
1 answer:
sweet [91]3 years ago
7 0
Slope intercept form = Y = Mx + B

15 = -3y + 21x

3y = 21x - 15

Y = 21/3 X - 15/3

Y = 7x - 5 = SI Form
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Write an equation in point slope form for the line that passes through (-5,6) and (-3,-9).
Finger [1]

\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad
(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-9-6}{-3-(-5)}\implies \cfrac{-9-6}{-3+5}\implies -\cfrac{15}{2}


\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-6=-\cfrac{15}{2}[x-(-5)]\implies y-6=-\cfrac{15}{2}(x+5)
\\\\\\
y-6=-\cfrac{15}{2}x-\cfrac{75}{2}\implies y=-\cfrac{15}{2}x-\cfrac{75}{2}-6\implies y=-\cfrac{15}{2}x-\cfrac{87}{2}

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3 years ago
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ladessa [460]

Answer:

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4 0
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soldi70 [24.7K]

Answer:

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3 years ago
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