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worty [1.4K]
3 years ago
15

given a set of numbers n= {1,3,4,5,7}. if event a is the drawing of a number less than 4 and event b is the drawing of an even n

umber, what is the probability that either event a or b will occur?
Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0
A OR b means that you add the individual probabilities...

P(<4)=2/5 and P(even)=1/5 so

P(<4 or even)=3/5
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(-yx^2)^2 • -2x^0y^3
sveticcg [70]
<span>(-yx^2)^2 • -2x^0y^3
= x^4y^2 (-2y^3)
= - 2x^4y^5</span>
6 0
3 years ago
Nate and his friends are building a skateboard ramp for an upcoming contest. The length of the ramp on the blueprint is 7.6 inch
ICE Princess25 [194]

Answer:

30.4 feet.

Step-by-step explanation:

We have been given the length of the ramp on the blueprint is 7.6 inches.  The scale on the blueprint is 1 inch to 4 feet. We are asked to find the actual length of the ramp.

We will use proportions to solve our given problem as:

\frac{\text{Actual length}}{\text{Scale length}}=\frac{4\text{ ft}}{1\text{ inch}}

Now, we will substitute the scale length of ramp in our proportion as:

\frac{\text{Actual length}}{7.6 \text{ Inches}}=\frac{4\text{ ft}}{1\text{ inch}}

\frac{\text{Actual length}}{7.6 \text{ Inches}}\cdot 7.6 \text{ Inches}=\frac{4\text{ ft}}{1\text{ inch}}\cdot 7.6 \text{ Inches}

\text{Actual length}=4\text{ ft}\cdot 7.6

\text{Actual length}=30.4\text{ ft}

Therefore, the actual length of the ramp would be 30.4 feet.

7 0
3 years ago
What is the length of C'D' ?<br> feet
Alinara [238K]

Answer:

7 feet

Step-by-step explanation:

The length of the line segment doesn't change if you reflect it over the line l.

4 0
2 years ago
The perimeter of a rectangle is 40 m. The length is 2 m more than two times the width. Find the length and the width of the rect
RideAnS [48]

Answer:

Length is 14

Width is 6

Step-by-step explanation:

Length = 2W + 2

Width = W

Perimeter is twice the length + twice the width

P = 40 = 2(2W+2) + 2W first simplify

40 = 4W + 4 + 2W  now combine terms

40 = 6W + 4 and subtract 4 from both sides

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5 0
3 years ago
Find the focus. y= -1/12 (x)² - 6
jolli1 [7]

Answer:

\Large \boxed{\sf\ \  (0,-9) \ \ }

Step-by-step explanation:

Hello,

We know that when the parabola equation is

   y=a(x-h)^2+k

the vertex is (h,k) and the focus is

   (h,k+\dfrac{1}{4a})

Here, the equation is

   y=-\dfrac{1}{12}x^2-6

so

   a=-\dfrac{1}{12}\\\\h = 0\\\\k =-6

So,

k+\dfrac{1}{4a}=-6-\dfrac{12}{4}=-6-3=-9

Then, the focus is

\large \boxed{\sf\ \  (0,-9) \ \ }

I attached the graph, included the focus so that you can see it :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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