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kifflom [539]
3 years ago
15

A solution with a pH of 11 has a [H+] of: 11

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
8 0
It’s B. 1 x 10-11

Explanation:

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A sample of aluminum is placed in a 25 ml graduated cylinder containing 10 mL of water. The level of water rises to 18 mL. Alumi
anastassius [24]

To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.

4 0
2 years ago
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What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L
Nonamiya [84]

Answer:

The pressure is 1, 22 atm.

Explanation:

We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).

0°C=273 K   25°C= 273 + 25= 298 K

PV=nRT   -----> P= (nRT)/V

P= (0,5 mol x 0,082 l atm /K mol x 298 K)/ 10 L

<em>P= 1, 2218 atm</em>

3 0
3 years ago
What are the molarity and the normality of a solution made
Nikitich [7]

Explanation:

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

Hence, calculate the molarity of given solution as follows.

     Molarity of citric acid = \frac{\text{mass of citric acid}}{\text{molar mass of citric acid}} \times \frac{1}{\text{volume of solution(L)}}

                                 = \frac{25 g}{192.13 g/mol} \times \frac{1}{0.75 L}

                                 = 0.173 M

As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.

          Normality = Molarity × no. of hydrogen or hydroxide ions

                            = 0.173 × 3

                            = 0.519 N

Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.

3 0
3 years ago
Calculate the radius of a tantalum (ta) atom, given that ta has a bcc crystal structure, a d ensity of 16.6 g/cm3, and an atomic
Sidana [21]

solution:

Ta is BCC, a=\frac{4}{\sqrt{3}r},n=2atoms/cell\\p=16.6gram/cm^3,A=180.9gram/mol\\P=\frac{A\times n}{N_{a}\times v}=\frac{180.9\frac{gram}{mol}\times 2 \frac{atom}{cell}}{6.023\times10^23\frac{atom}{mol}\times(\frac{4}{\sqrt{3}\times r})^3\frac{cm^3}{cell}}\\=16.6\frac{gram}{cm^3}\\r=(\frac{180.9\times2}{16.6\times6.023\times10^23\times(\frac{4}{\sqrt{3}})^3})^\frac{1}{3}\times10^8


4 0
3 years ago
Solute particles can be:____
Reptile [31]

Solute particles can be atoms, ions or molecules.

Explanation:

Solute is the material which has to be mixed in the solvent to prepare a solution. So the concentration of solute should be less than the solvent. Also the solute and solvent should be of same nature other they will not dissolve with each other. The solute can be made up of atoms, ions or molecules depending upon the solvent. If the solvent concentration is in moles, then the solute concentration can be taken as atoms, ions or molecules. Also the saturation point plays a main role in deciding the kind of particles taken for the solute.

8 0
2 years ago
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