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kifflom [539]
3 years ago
15

A solution with a pH of 11 has a [H+] of: 11

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
8 0
It’s B. 1 x 10-11

Explanation:

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In a calorimeter, the equilibrium temperature of copper in water is determined. if the water is replaced with a liquid that has
Feliz [49]
The equilibrium temperature will increase
4 0
3 years ago
How many minutes are in 17 years?
Anarel [89]

Explanation:

8935200 mins plzzzźzzz mark it brainest

3 0
3 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
How many electrons fit in the part of the third energy level shown
makkiz [27]

Answer:

18 electrons

Explanation:

Note: The third energy level can actually hold up to 18 electrons, so it is not really filled when it has 8 electrons in it.

5 0
2 years ago
Volume of 8.625 g of sulphur di oxide at RTP in cm3
frutty [35]

Answer:

The volume of 8.625 g of sulphur dioxide at RTP is approximately 3,230.84 cm³

Explanation:

The question requires the determination of the volume occupied by the gas based on the molar volume of a gas at STP

The given parameters of the sulphur dioxide, SO₂, gas are;

The mass of the given SO₂ gas = 8.625 g

The molar mass of SO₂ = 64.07 g/mol

The number of moles, 'n', in the given sample of SO₂ gas = Mass of SO₂/(Molar Mass of SO₂)

∴ The number of moles of SO₂ in the gas sample = 8.625 g/(64.07 g/mol) ≈ 0.134618386 moles

The molar volume of a gas at RTP is approximately 24 dm³/mole

24 dm³ = 24,000 cm³

∴ The molar volume of a gas at RTP is approximately 24,000 cm³/mole

The volume occupied by a gas at RTP = (The number of moles of the gas) × (The Molar Volume of a gas at RTP)

∴ The volume occupied by the 8.625 g of SO₂ gas at RTP = 0.134618386 moles × 24,000 cm³/mole ≈ 3,230.84 cm³

The volume occupied by the 8.625 g of SO₂ gas at RTP ≈ 3,230.84 cm³.

7 0
3 years ago
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