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vova2212 [387]
3 years ago
8

A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0 seconds. What is the skateboarder’

s acceleration?
*Please only answer if you know - and ABSOLUTLEY NOOOOOOOO LINKS*
Thank you! :)
Physics
1 answer:
ki77a [65]3 years ago
8 0

Answer:

-2.33 m/s²

Explanation:

The computation of the skateboarder’s acceleration is shown below;

Acceleration means the change in velocity per unit with respect to time.

In the given case, the initial velocity is 7 m/s.

As in the question it is mentioned that  it comes to a stop, so the final velocity would be zero.

And, The time elapsed is 3 seconds.

Now the following equation should be used  

a = (v,final - v,initial) ÷ t

=  (0 - 7)/3

= -2.33 m/s²

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time t=130 ms

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\phi =B\cdot A

change in Flux d\phi =(B_f-B_i)A

Emf induced is e=\frac{\mathrm{d} \phi}{\mathrm{d} t}

e=\frac{(1.5)\cdot 7.069\times 10^{-6}}{130\times 10^{-3}}

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18. How much force would it take to push another, larger friend who has a mass of 70 Kg to accelerate
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A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A
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Answer:

\omega_f = 585.37 \ rev/s

Explanation:

given,

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I_{wheel} = Mr²

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I' = Mr² + mr²

using conservation of angular momentum

I \omega_i = I' \omega_f

(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f

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3\times 800 = (3+1.1)\times \omega_f

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riadik2000 [5.3K]

Answer:

0.6983 m/s

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v = 0.6983 m/s

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4 years ago
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