Answer:
40.91 m/s
Explanation:
w = angular velocity of the ball about the elbow joint = 30.3 rad/s
r = radius of circular turn = distance of the ball from the elbow joint = 1.35 m
v = linear velocity of the ball
Linear velocity of the ball is given as
v = r w
Inserting the values given above in the equation
v = (1.35) (30.3)
v = 40.91 m/s
Answer: Height should be 44.1 m.
Explanation:
Pressure exerted by stationary water stored at a height is,
P = ρgh
4.41 ×
= 1000× 10× h
solving we get,
h = 44.1 m
A small 20-kg canoe is floating downriver at a speed of 2 m/s. 40 J is the canoe’s kinetic energy.
Answer: Option A
<u>Explanation:</u>
The given canoe has the mass and is being given to move at a speed. Therefore the kinetic energy of the canoe can be calculated using the following method,
Given that mass of the canoe = 20 kg and its speed =1 m/s
As we know that the Kinetic energy has the formula,

Therefore, substituting the value into the equation, we get,
= 40 J
Answer:
Option A

Explanation:
From fundamental equation of motion
where v is the final velocity, u is the initial velocity, a is the acceleration of the body and s is the displacement.
Since the initial velocity is zero
Making acceleration, a the subject of the formula then

Substituting 5 m/s for v and 2.5 m for s then
