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3 years ago

Which of the following statements regarding radiation are FALSE?

Chemistry

1 answer:

kari74 [83]3 years ago

5 0

Answer:

All of the given statements are true.

Explanation:

All the elements are heavier than Bismuth (Bi) are radioactive.

The time for half of the original sample to spontaneous decay is called half life ( $t_{1/2}$ )

$t_{1/2}=\frac{ln\:2}{\lambda}\\\lambda\:is\:the\:radioactive\:decay\:constant$

All radioactive elements are spontaneously decaying towards formation of a stable element.

Radioactive elements undergo decay in order to attain stability.

Radioactivity is a natural part of our environment. The earth also contains several primordial long-lived radioisotopes that have survived to the present in significant amounts.

Hence, all the given statements are true.

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A sample of crude sodium iodide was analysed by the following rection.

amm1812

A sample of crude sodium iodide was analyzed by the following balanced reaction. The oxidation number of S in SO₄²⁻ is +6.

8 I⁻ + 6 H₂O + SO₄²⁻ → 4 I₂ + H₂S + 10 OH⁻

Let's consider the following unbalanced redox reaction.

I⁻ + SO₄²⁻ → I₂ + H₂S

The oxidation number of I goes from -1 (I⁻) to 0 (I₂) so it is oxidized.
The oxidation number of S goes from +6 (SO₄²⁻) to -2 (H₂S) so it is reduced.

The corresponding half-reactions are:

I⁻ → I₂

SO₄²⁻ → H₂S

We will perform the mass balance adding OH⁻ and H₂O where appropriate.

2 I⁻ → I₂

6 H₂O + SO₄²⁻ → H₂S + 10 OH⁻

Then, we will perform the charge balance adding electrons where appropriate.

2 I⁻ → I₂ + 2 e⁻

8 e⁻ + 6 H₂O + SO₄²⁻ → H₂S + 10 OH⁻

Finally, we will multiply the first half-reaction by 4 and the second by 1, and add them.

4 × (2 I⁻ → I₂ + 2 e⁻)

1 × (8 e⁻ + 6 H₂O + SO₄²⁻ → H₂S + 10 OH⁻)

------------------------------------------------------------

8 I⁻ + 6 H₂O + SO₄²⁻ → 4 I₂ + H₂S + 10 OH⁻

A sample of crude sodium iodide was analyzed by the following balanced reaction. The oxidation number of S in SO₄²⁻ is +6.

8 I⁻ + 6 H₂O + SO₄²⁻ → 4 I₂ + H₂S + 10 OH⁻

Learn more: brainly.com/question/2671074

6 0

3 years ago

The melting points for the compounds li2s, rb2s, and k2s are 900°c, 530°c, and 840°c, respectively. list these three compounds i

Mila [183]

Answer: The order of increasing lattice energy is $Li_2S>K_2S>Rb_2S$

Explanation: Lattice energy is defined as the energy required to break the intermolecular force that is responsible for the formation of a lattice.

Melting point is defined as the temperature at which solid gets converted into liquid due to the weakening of the bonds in the solid form.

Relation between lattice energy and Melting point:

The relationship between these two is direct.

$\text{Lattice energy}\propto \text{Melting point}$

More the melting point of a compound, more will be its lattice energy.

Order of increasing Lattice energy will be:

$Li_2S>K_2S>Rb_2S$

7 0

3 years ago

(a) The rate of the reaction in terms of the "disappearance of reactant" includes the change in the concentration of the

Vaselesa [24]

Answer:

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

Explanation:

Average rate of the reaction is defined as ratio of change in concentration of reactant with respect to given interval of time.

$R_{avg}=-\frac{[A]_2-[A]_1}{t_2-t_1}$

Where :

$A_1$ = initial concentration of reactant at $t_1$ .

$A_2$ = Final concentration of reactant at $t_2$ .

2A+3B → 3C+2D

$R_{avg}=-\frac{1}{2}\frac{[A]_2-[A]_1}{t_2-t_1}$

The concentration of A at ( $t_1=0 seconds$ ) = $A_1=0.0400 M$

The concentration of A at ( $t_2=20 seconds$ ) = $A_2=0.0240 M$

The average rate of reaction in terms of the disappearance of reactant A in an interval of 0 seconds to 20 seconds is :

$R_{avg}=-\frac{1}{2}\times \frac{0.0240 M-0.0400 M}{20-0}=0.0004 M/s$

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

6 0

3 years ago

Which of the following elements have the same valence electrons as germanium

Elina [12.6K]

Carbon, Lead and Silicon all have the same amount of valence electrons as Germanium. This can be determined by looking at their position on the periodic table. Within each column (group) all the elements have the same amount of valence electrons. This explains why they will all have very similar chemical properties.

3 0

3 years ago

Write formulas for each of the following compounds:

zloy xaker [14]

A. Phosphorus (III) iodide:PI3
b. Sulfur (II) chloride :SCl2
c. Carbon (IV) sulfide :CS2
d. Nitrgoen (V) oxide:N2O5
hope it helps

6 0

3 years ago