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erma4kov [3.2K]
3 years ago
11

Which of the following statements regarding radiation are FALSE?

Chemistry
1 answer:
kari74 [83]3 years ago
5 0

Answer:

All of the given statements are true.

Explanation:

All the elements are heavier than Bismuth (Bi) are radioactive.

The time for half of the original sample to spontaneous decay is called half life (t_{1/2})

t_{1/2}=\frac{ln\:2}{\lambda}\\\lambda\:is\:the\:radioactive\:decay\:constant

All radioactive elements are spontaneously decaying towards formation of a stable element.

Radioactive elements undergo decay in order to attain stability.

Radioactivity is a natural part of our environment. The earth also contains several primordial long-lived radioisotopes that have survived to the present in significant amounts.

Hence, all the given statements are true.

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Answer:

There will be formed 13.82 grams of Fe3O4.

Explanation:

<u>Step 1:</u> the balanced reaction

3 Fe(s) + 4 H2O(l) —— Fe3O4(s) + 4 H2(g)

We see that for 3 moles Fe consumed, there will be consumed 4 moles of H20 and produced 1 mole of Fe3O4 and 4 moles of H2.

<u>Step 2:</u> Calculating moles

⇒mole = mass / Molar mass

⇒moles Fe = 10g / 55.845g/mole = 0.179 moles

⇒moles H2O = 10g / 18g/mole = 0.5556 moles

Since we have 4 moles of H2O consumed for 3 moles of Fe, this means that for 0.179 moles of Fe, we have :

0.179 / 4 *3 = 0.2387 moles of H2O consumed

This means that Fe will be completely consumed and there will remain 0.2387 moles of H2O.

Fe is the limiting reactant and H2O is in excess.

<u>Step 3: </u>Calculate moles of Fe3O4

For 3 moles of Fe consumed, we have 1 mole of Fe3O4 produced.

This means, that for 0.179 moles of Fe consumed, we have 0.179/3 =0.05967 molesof Fe3O4 produced.

<u>Step 4:</u> Calculating mass of Fe3O4

mass= number of moles * Molar mass

mass Fe3O4 = 0.05967 mole * 231.55g/mole = 13.8166 g ≈ 13.82grams of Fe3O4

There will be formed 13.82 grams of Fe3O4.

5 0
3 years ago
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